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Eddi Din [679]
2 years ago
7

Consult the figure. To find the length of the span of a proposed ski lift from A to B,

Mathematics
1 answer:
Natasha2012 [34]2 years ago
3 0

The figure is an illustration of laws of sines, and the distance from A to B is 2534 feet

<h3>How to determine the distance AB?</h3>

The given parameters are:

DAB = 25°

L = 1700

ACB = 15°

Start by calculating the measure of angles CAB and ABC

CAB = 180 - DAB

This gives

CAB = 180 - 25°

CAB = 155°

Also, we have:

ABC = 180 - CAB - ACB

ABC = 180 - 155 - 15

ABC = 10°

The length AB is then calculated using the following laws of sines

\frac{AB}{\sin(C)} = \frac{L}{\sin(B)}

This gives

\frac{AB}{\sin(15)} = \frac{1700}{\sin(10)}

Make AB the subject

AB =  \frac{1700}{\sin(10)} *\sin(15)

Evaluate

AB =  2533.8151116

Approximate

AB = 2534

Hence, the distance from A to B is 2534 feet

Read more about laws of sines at:

brainly.com/question/16955971

#SPJ1

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Answer:

h ≅ 16.29 cm

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Step-by-step explanation:

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tan  \theta= \dfrac{8}{16}

tan  \theta= \dfrac{1}{2}

∴

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r = \dfrac{h}{2}

The volume (V) of the cone is expressed as:

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V = \dfrac{\pi h^3}{3\times 4}

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\dfrac{0^3}{3} = -48(0) + c

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\dfrac{h^3}{3}= -48 t + 0

\dfrac{h^3}{3}= -48 t

t = 30

\implies h = (-48(30))^{1/3}

h = 16.2865

h ≅ 16.29 cm

Thus;

from -12 \pi = \dfrac{ \pi h^2}{4} \dfrac{dh}{dt}

\dfrac{-12 \pi} { \dfrac{ \pi h^2}{4} } =\dfrac{dh}{dt}

\dfrac{dh}{dt} = \dfrac{-12 \pi} { \dfrac{ \pi h^2}{4} }

\dfrac{dh}{dt}=\dfrac{-12 \times 4} { {16.29^2} }

\mathbf{\dfrac{dh}{dt}= -0.1809 \ cm/s}

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Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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