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timurjin [86]
3 years ago
7

A race car driving under the caution flag at 80 feet per second begins to accelerate at a constant rate after the warning flag.

The distance traveled since the warning flag in feet is characterized by 30t 2 + 80t, where t is the time in seconds after the car starts accelerating again.How long does it take the car to travel 30 feet after it begins accelerating?
Mathematics
1 answer:
Colt1911 [192]3 years ago
6 0

Answer: 1/3 sec or 0.333 sec


Step-by-step explanation:


d = 30*t^2 + 80*t = 30

putting into quadratic form, a*t^2 + b*t + c = 0

30*t^2 + 80*t - 30 = 0 where: a = 30 b = 80 c = -30

solve quadratic:

t = [-b + sqrt( b^2 - 4*a*c)]/2*a

substitute in values above

therefore, t = 1/3 sec or 0.333 sec

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So we know if x=large dogs and y=small dogs, then x+y=49.
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We can then simplify it to 2x+36=49.
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What is the answer of this question ?
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Answer:

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Step-by-step explanation:

hoped I helped:)

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