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EleoNora [17]
2 years ago
7

How many permutations of a 7-digit phone number exist if any number 0-9 may be used but repetition is not allowed?

Mathematics
1 answer:
Blizzard [7]2 years ago
5 0

Answer:

10!/3!

Step-by-step explanation:

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A red car is driving along the road in the direction of the police car and is 130 feet up the road from the location of the poli
pishuonlain [190]

Complete question:

A police car is located 50 feet to the side of a straight road. A red car is driving along the road in the direction of the police car and is 130 feet up the road from the location of the police car. The police radar reads that the distance between the police car and the red car is decreasing at a rate of 75 feet per second. How fast is the red car actually traveling along the road.

Answer:

The red car is traveling along the road at 80.356 ft/s

Step-by-step explanation:

Given

Police car is 50 feet side off the road

Red car is 130 feet up the road

Distance between them is decreasing at the rate of 75 feet per sec

Let x be how far the police is off the road.

Let y be how far the red car is up the road.  

Let h be the distance between the police and the red car.

This forms a right triangle so we can use the Pythagorean theorem, to solve for h

h² = x² + y²

h² = 50² + 130²

h² = 19400

h = √19400

h = 139.284 ft

Again;

Let dx/dt be how fast the police is traveling toward the road.

Let dy/dt  be how fast the red car is traveling along the road.

Let dh/dt be how fast the distance between the police and the car is decreasing.

Recall that, h² = x² + y² (now differentiate with respect to time, t)

2h(dh/dt) = 2x(dx/dt) + 2y(dy/dt)

divide through by 2

h(dh/dt) = x(dx/dt) + y(dy/dt)

since the police car is not, dx/dt = 0

and dy/dt is the how fast is the red car actually traveling along the road

139.284(75) = 50(0) + 130(dy/dt)

10446.3 = 0 + 130(dy/dt)

dy/dt = 10446.3 / 130

dy/dt = 80.356 ft/s

Therefore, the red car is traveling along the road at 80.356 ft/s

6 0
3 years ago
What is the LCM of x^2+5 and x^2+10x+25?
avanturin [10]

Answer:

(x+5)²(x²+5)

Step-by-step explanation:

Given two functions x²+5 and x²+10x+25, to get their Lowest common factor, we need to to first factorize x²+10x+25

On factorising we have:

x²+5x+5x+25

= x(x+5) +5(x+5

= (x+5)(x+5)

= (x+5)²

The LCM can be calculated as thus

| x²+5, (x+5)²

x+5| x²+5, (x+5)

x+5| x²+5, 1

x²+5| 1, 1

The factors of both equation are x+5 × x+5 × x²+5

The LCM will be the product of the three functions i.e

(x+5)²(x²+5)

This hives the required expression.

5 0
3 years ago
How do I do this question
aliya0001 [1]

Answer:

Step-by-step explanation:

Join OB.

∠A=∠A  (common)

\frac{AP}{AO} =\frac{\frac{1}{2} AO}{AO} =\frac{1}{2} \\\frac{AQ}{AB} =\frac{\frac{1}{2} AB}{AB} =\frac{1}{2} \\\frac{AP}{AO} =\frac{AQ}{AB}

∴ ΔAPO and ΔAOB are similar.

\frac{PQ}{OB} =\frac{1}{2} \\

∠P=∠O

∠Q=∠B

So PQ║OB

Similarly RS║OB

∴PQ║RS

7 0
3 years ago
4over 5 divided by 1 over 10
MAVERICK [17]
4/5 divided by 1/10 = 4/5 x 10/1 = 40/5 = 8
3 0
3 years ago
F(x+h) = (x+h)² + 3(x+h)^3<br><br> How would I distribute this?
Leno4ka [110]

Answer:

f(x + h) = 3x³ + x² + 9h²x + 3h³ + h² + 9hx² + 2hx

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Distributive Property
  • Expand by FOIL (First Outside Inside Last)
  • Combining like terms

Step-by-step explanation:

<u>Step 1: Define function</u>

f(x) = x² + 3x³

f(x + h) is x = x + h

<u>Step 2: Simplify</u>

  1. Substitute:                              f(x + h) = (x + h)² + 3(x + h)³
  2. Expand by FOILing:               f(x + h) = (x² + 2hx + h²) + 3(x + h)³
  3. Rewrite:                                  f(x + h) = (x² + 2hx + h²) + 3(x + h)²(x + h)
  4. Expand by FOILing:               f(x + h) = (x²+2hx+h²) + 3(x² + 2hx + h²)(x+h)
  5. Distribute/Expand:                 f(x + h) = (x²+2hx+h²) + 3(x³+3hx²+3h²x+h³)
  6. Distribute 3:                            f(x + h) = (x²+2hx+h²)+(3x³+9hx²+9h²x+3h³)
  7. Combine like terms:               f(x + h) = 3x³+x²+9h²x+3h³+h²+9hx²+2hx
3 0
2 years ago
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