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Debora [2.8K]
2 years ago
7

Jessica purchased a DVD that was on sale for 12% off. The sales tax in her county is 3%. Let y represent the original price of t

he DVD. Write an expression that can be used to determine the final cost of the DVD.
Mathematics
2 answers:
Zanzabum2 years ago
7 0

Answer:

is it y=12x+3

Step-by-step explanation:

x=DVD. DVD =12

seraphim [82]2 years ago
4 0

Answer:

is it y=12x+3

Step-by-step explanation:

x=DVD. DVD =12

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A line that passes through point (3,7) and has a slope of 3/4. The equation of the line is ? If point a(x,5) lies on the line ,
Amanda [17]
Y = mx + b
slope(m) = 3/4
(3,7)...x = 3 and y = 7
now we sub...we r looking for b, the y int
7 = 3/4(3) + b
7 = 9/4 + b
7 - 9/4 = b
28/4 - 9/4 = b
19/4 = b

equation is : y = 3/4x + 19/4...lets put this in standard form

y = 3/4x + 19/4
-3/4x + y = 19/4...multiply by -4
3x - 4y = -19 <== standard form

if (x,5) is on the line
3x - 4y = -19.....sub in 5 for y
3x - 4(5) = -19
3x - 20 = -19
3x = -19 + 20
3x = 1
x = 1/3 <====so point a = (1/3,5)
5 0
2 years ago
A. 22.59<br> B. 14.34<br> C. 20.48<br> D. 10.70
REY [17]

Answer:

  B.  14.34

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationship between the side opposite the angle of interest and the hypotenuse:

  Sin = Opposite/Hypotenuse

For the given triangle, this means ...

  sin(35°) = b/25

  b = 25·sin(35°)

  b ≈ 14.34

6 0
2 years ago
4x+y=8 and x+3y=8 graphed
IRISSAK [1]
standard \ linear \ equation\ :\\\\y=ax+b\\\\ \begin{cases} 4x+y=8\ \ |\ subtract\ 4x\ to\ both\ sides\\ x+3y=8 \ \ |\ subtract\ x\ to\ both\ sides \end{cases}\\\\\begin{cases} y=-4x+8 \\ 3y=-x+8\ \ | \ divide \ each \ term \ by \ 3 \end{cases}

\begin{cases} y=-4x+8 \\ y=-\frac{1}{3}x+\frac{8}{3} \end{cases}\\\\y=-4x+8\\ To \ find \ the \ x-axis \ intersection \ point, \\set \ y \ equal \ to \ zero \ and \ solve \ for \ x : \\ \\y=0 \ \to 0=-4x+8\\\\4x=8 \ \ | \ divide \ both \ sides\ by\ 4 \\\\x=2\\\\ point : \ \ (2,0)
 
To \ find \ the \ y-axis \ intersection \ point, \\set \ x \ equal \ to \ zero \ and \ solve \ for \ y : \\ \\x=0 \ \to y=-4 \cdot 0+8\\ y=8 \\ point: \ \ (0,8)


y=-\frac{1}{3}x+\frac{8}{3}\\\\ \ the \ x-axis \ intersection \ point \\ \\y=0 \ \to 0=-\frac{1}{3}x+\frac{8}{3}\\ \frac{1}{3}x=\frac{8}{3} \ \ | \ multiply\ both\ sides\ by\ 3 \\\\x=8 \\\\point: \ \ (8,0)

the \ y-axis \ intersection \ point \\ \\x=0 \ \to y=-\frac{1}{3} \cdot 0+\frac{8}{3} \\ y=\frac{8}{3} \\ point : \ \ (0,\frac{8}{3})


Answer :\\\\ \begin{cases} y=-4x+8 \ \ | \ multiply \ each \ term \ by \ (-3) \\ 3y=-x+8 \end{cases}\\\begin{cases} -3y=12x-24 \\ 3y=-x+8 \end{cases}\\+-------\\0=11x-16\\11x=16\ \ | \ divide \ both \ sides\ by\ 11\\x=\frac{16}{11}

y=-4 \cdot \frac{16}{11}+8 \\ y=- \frac{ 64}{11}+\frac{88}{11}\\y= \frac{24}{11}\\\\\begin{cases} x=\frac{16}{11} \\ y=\frac{24}{11} \end{cases}


3 0
3 years ago
Fred is 58 yes old, and Irene is 18. How many years ago was Fred 5 times as old as Irene. Algebra must be used
Sedaia [141]
So let's take a peek at both's ages, keep in mind, every year, is 1year added to Irene and 1year added to Fred
so... if we look at their ages  \bf \begin{array}{ccllll}&#10;fred&irene\\&#10;\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\&#10;58&18\\&#10;57&17\\&#10;56&16\\&#10;55&15\\&#10;...&...&#10;\end{array}

notice, Fred is always 40years older than Irene

thus, whatever age Irene is, let's say "i", then Fred is " i + 40 "

now, when is Fred 5 times Irene's age or 5*i or 5i? well, 

f = fred's age    i = irene's age

f = i + 40
now if  f = 5i

5i = i + 40   <---    solve for "i" to see how old Irene was then
3 0
3 years ago
How to rationalize <img src="https://tex.z-dn.net/?f=%5Cfrac%7B17%7D%7B4%5Csqrt%7B1%7D7%20%7D" id="TexFormula1" title="\frac{17}
dem82 [27]

Answer:

\frac{\sqrt{17}}{4}

Step-by-step explanation:

Rationalizing the denominator of a fraction is when one multiplying fraction such that it removes any radical from the denominator. This can be done by multiplying both the numerator and the denominator by the radical that is present in the denominator. In fractional terms, a number over itself is equal to one, therefore, doing this would keep the equation true. After multiplying, one will simplify the resulting fraction.

\frac{17}{4\sqrt{17}} * \frac{\sqrt{17}}{\sqrt{17}}\\\\= \frac{17\sqrt{17}}{4(17)}\\

Simplify like factor found in both the numerator and the denominator,

\frac{17\sqrt{17}}{4(17)}\\\\= \frac{\sqrt{17}}{4}

8 0
2 years ago
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