Five thirds of a right angle?

Can someone please answer. There is a picture. It is only one question. Thank you so much!

Charra [1.4K]

We can check each of these using the Pythagorean Theorem, $a^2 + b^2 = c^2$
Option A:
$.5^2 + 1.2^2 = 1.3^2

$
.25 + 1.44 = 1.691.69 = 1.69
This option works
Option B
$1^2 + 2^2 = 3^2$
1 + 4 = 9
5 ≠ 9
This option does not work, but let's check the others to make sure
Option C:
$6^2 + 8^2 = 10^2$
36 + 64 = 100
100 = 100
This option works
Option D:
$3^2 + 4^2 = 5^2$
9 + 16 = 25
25 = 25
This option works

So, after doing the calculations, we see that option B does not work

6 0

3 years ago

Please help ASAP!! 31 points and brainliest!

jolli1 [7]

A relation is a function if it has only One y-value for each x-value. Functions f(2/3)=2/9 for f(x)=2x²-4x+2 and f(1/4)==-21/4 for f(x)=4x²+2x-6

<h3>What is a function?</h3>

A relation is a function if it has only One y-value for each x-value.

The given function is

f(x)=2x²-4x+2

Put x=2/3

f(2/3)=2(2/3)²-4(2/3)+2

=2(4/9)-8/3+2

=8/9-8/3+2

=(8-24+18)/9

f(2/3)=2/9

Now f(x)=4x²+2x-6

Put x=1/4

f(1/4)=4(1/4)²+2(1/4)-6

=4/16+2/4-6

=1/4+1/2-6

= 1+2-24/4

f(1/4)==-21/4

Hence functions f(2/3)=2/9 for f(x)=2x²-4x+2 and f(1/4)==-21/4 for f(x)=4x²+2x-6

To learn more on Functions click:

brainly.com/question/21145944

#SPJ1

3 0

1 year ago

How do I do this help

tatuchka [14]

6÷40.5= $6.75 per hour
8÷54= $6.75 per hour
y= 6.75x

5 0

3 years ago

A large but sparsely populated county has two small hospitals, one at the south end of the county and one at the north end. The

Readme [11.4K]

Answer:

Step-by-step explanation:

Probability distribution of this type is a vicariate distribution because it specifies two random variable X and Y. We represent the probability X takes x and Y takes y by

f(x,y) = P((X=x,Y=y) ,

and given that the random variables are independent the joint pmf isbgiven by:

f(x,y) = fX(x) .fY(y) and this gives the table (see attachment)

(b) the required probability is given by considering X=0,1 and Y =0,1

f(x,y) = sum{(P(X ≤ 1, Y ≤ 1) }

= [0.1 +0.2 ] × [0.1 + 0.3]

= 0.3 × 0.4

= 0.12

Now we find

fX(x) = sum{[f(x.y)]} for y =0, 1 and similarly for fY(y)= sum{[f(x,y)]} for x=0, 1

fX(x) = sum{[f(x,y)]}= 0.1+0.3

= 0.4

fY(y) = sum{[f(x.y)]} = 0.1 + 0.2

= 0.3

Since fY(y) × fX(x) = 0.4 × 0.3

= 0.12

Hence f(x,y) = fX(x) .fY(y), the events are independent

(c) the required event is give by: [P(X<=1, PY<=1)]

= P(X<=1) . P(Y<=1)

= [sum{[f(x.y]} over Y=0,1] × [sum{[f(x.y)]}, over X= 0, 1

= 0.4 × 0.3

= 0.12

(d) the required event is given by the idea that: either The South has no bed and the North has or the the North has no bed and the South has. Let this event be A

A =sum[(P(X = 1<= x<= 4, Y =0)] + sum[P(X =0 Y= 1 <= x <= 3)]

A = [0.02 + 0.03 + 0.02 + 0.02] + [0.03 + 0.04 + 0.02]

A = [0.09] + [ 0.09]

A = 0.18

Pls note the sum of the vertical column X=2 is 0.3

3 0

3 years ago

44 is the same as 113 more than w

Setler79 [48]

Answer:

Step-by-step explanation:

44=113+w

w=-69

5 0

3 years ago