Answer:
14.8% of H2O2
Explanation:
Based on the redox reaction of H2O2/MnO4- is:
2MnO4- + 5H2O2 + 6H+ ⇄ 2Mn2+ + 5O2 + 8H2O
<em>2 moles of KMnO4 react with 5 moles of H2O2</em>
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To solve this question we need to find the moles of KMnO4 until reach the endpoint. Using the balanced reaction, we can find the moles of H2O2 that must be converted to grams using its molar mass -Molar mass H2O2: 34.015g/mol-:
<em>Moles KMnO4:</em>
0.0297L * (1.4686eq/L) = 0.04362eq MnO4- * (1mol / 5eq) = 0.008723 moles MnO4-
<em>Moles H2O2:</em>
0.008723 moles MnO4- * (5mol H2O2 / 2mol MnO4-) = 0.02181 moles H2O2
<em>Mass H2O2:</em>
0.02181 moles H2O2 * (34.015g/mol) = 0.7418g H2O2
<em>%:</em>
0.7418g H2O2 / 5.0mL * 100
<h3>14.8% of H2O2</h3>
Answer:
The correct option is : c. external sphincter muscle of the bladder
Explanation:
The process of excretion of urine from the urinary bladder to outside the body through the urethra is known as Micturition. The other names for micturition are urination and voiding.
In a normal human being, the process of micturition requires both the voluntary and involuntary nervous system components.
The external sphincter is a voluntary muscle. For urination to occur the external sphincter muscle must be relaxed.
Therefore, the process of voiding urine begins if the external sphincter muscle relaxes voluntarily.
