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2 years ago

Which of the following is equivalent to the complex number i^5

Mathematics

1 answer:

ELEN [110]2 years ago

5 0

Answer:

Step-by-step explanation:

i = $\sqrt{-1}$ ⇒ i² = ( $\sqrt{-1}$ )² = - 1 , then

$i^{5}$

= i² × i² × i

= - 1 × - 1 ×i

= 1 × i

= i

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The function f(x)=3x+12x+11 can be written in vertex form as?

solmaris [256]

y = -3(x - 2)^2 + 1 x-coordinate of vertex: x = -b/(2a) = -12/-6 = 2 y-coordintae of vertex: y(2) = -12 + 24 - 11 = 1 Vertex form: y = -3(x - 2)^2 + 1 Check. Develop y to get back to standard form: y = -3(x^2 - 4x + 4) + 1 = -3x^2 + 12x - 11.

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3 years ago

Sunflower produce approximately 50 seeds per flower. If one ounce of sunflower seeds contain an average of 72 seeds, how many fl

ra1l [238]

Given :

Sunflower produce approximately 50 seeds per flower.

If one ounce of sunflower seeds contain an average of 72 seeds.

To Find :

How many flowers are needed to produce 2 pounds of seeds.

Solution :

1 pound = 16 ounces .

So , 2 pound = 32 ounces .

Number of seeds in 2 pounds of seeds, n = 32×72 = 2304 .

Number of flowers are :

$N=\dfrac{2304}{50}=46.08$

So , approximate number of flower required are 46.

Hence, this is the required solution.

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3 years ago

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olganol [36]

Answer:

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3 years ago

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chloe and jack play 4 games. the probability that chloe wins any game is 4/5. what is the probability that chloe wins for the 1s

Iteru [2.4K]

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3 years ago

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Determine the next step for solving the quadratic equation by completing the square.

Studentka2010 [4]

Answer:

The solutions are $x=\frac{1+\sqrt{7}}{2}$ and $x=\frac{1-\sqrt{7}}{2}$

Step-by-step explanation:

we have

$0=-2x^{2}+2x+3$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$-3=-2x^{2}+2x$

Factor the leading coefficient

$-3=-2(x^{2}-x)$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$-3-0.5=-2(x^{2}-x+0.5^{2})$

$-3.5=-2(x^{2}-x+0.5^{2})$

Rewrite as perfect squares

$-3.5=-2(x-0.5)^{2}$

$7/4=(x-0.5)^{2}$

square root both sides

$x-0.5=(+/-)\sqrt{\frac{7}{4}}$

$x-\frac{1}{2}=(+/-)\frac{\sqrt{7}}{2}$

$x=\frac{1}{2}(+/-)\frac{\sqrt{7}}{2}$

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$x=\frac{1-\sqrt{7}}{2}$

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3 years ago