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Alika [10]
3 years ago
6

What is the x of x^2-7x-30=0

Mathematics
1 answer:
Alexxx [7]3 years ago
7 0
The 'x' in x^2-7x-30=0 is 4.
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Write the equation of a line that is perpendicular to -2/7x+9 that passes through the point (4, -6)
Anna11 [10]

Answer:

7y + 2x + 34 = 0

Step-by-step explanation:

The gradient for perpendicular, m = -2/7

The formular equation, y - y1 = m(x - x1)

The equation of line through (4, -6) is:

y - (-6) = -2/7(x - 4)

y + 6 = -2x/7 + 8/7

7y + 42 + 2x - 8 = 0

7y + 2x + 34 = 0

6 0
3 years ago
Read 2 more answers
An indoor trampoline park has an admission fee, plus an hourly charge. The graph displays the total cost from 3, 4, 5, and 6 hou
defon

Answer:

 $4.5 per hour

Step-by-step explanation:

Hope this was accurate and help full. I hope you have a lovely day!

3 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASAP!!!!!! I WILL LOVE FOREVER LOL!!!
const2013 [10]

Point-slope form:  y - y₁ = m(x - x₁)

(m is the slope, (x₁, y₁) is the point you are given that is on the line)

You know:

m = 5

(x₁, y₁) = (-2, -3)         So substitute/plug it into the equation

y - y₁ = m(x - x₁)

y - (-3) = 5(x - (-2))   (two negative signs cancel each other out and become positive)

y + 3 = 5(x + 2)    Your answer is A

5 0
3 years ago
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a video game has 35 levels in it if you beat 5 of the levels what is the ratio of levels left to the levels that have been beate
marta [7]

We have 35 - 5 = 30 levels left to beat.

The question is asking us for the levels left to beat, to the ones that already have been beaten:

30 : 5

Simplified;

6 : 1

8 0
3 years ago
The table gives estimates of the world population, in millions, from 1750 to 2000. year population year population 1750 790 1900
Tems11 [23]
The poopulation exponential model is given by

P(t)=P_0e^{kt}

Where, P(t) is the population after year t; Po is the initial population, t is the number of years from the starting year; k is the groth constant.

Given that the population in 1750 is 790 and the population in 1800 is 970, we obtain the population exponential equation as follows:

970=790e^{50k} \\  \\ \Rightarrow e^{50k}=1.228 \\  \\ \Rightarrow 50k=\ln{1.228}=0.2053 \\  \\ \Rightarrow k=0.0041

Thus, the exponential equation using the 1750 and the 1800 population values is P(t)=790e^{0.0041t}

The population of 1900 using the 1750 and the 1800 population values is given by

P(t)=790e^{0.041\times150} \\  \\ =790e^{0.6158}=790(1.8511) \\  \\ =1,462

The population of 1950 using the 1750 and the 1800 population values is given by

P(t)=790e^{0.041\times200} \\  \\ =790e^{0.821}=790(2.2729) \\  \\ =1,796

From the table, it can be seen that the actual figure is greater than the exponential model values.
7 0
3 years ago
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