4 and 1 third times 6 4 1/3 x 6

The width of a rectangle is 4 feet and the diagonal length of he rectangle is 13 feet what is the measurement is the closest to

AURORKA [14]

Answer:

The length is APPROXIMATELY equal to 12.4.

Step-by-step explanation:

Use the converse of the Pythagorean Theorem ( $a^{2}$ + $b^{2}$ = $c^{2}$ [where "c" is both the longest side and the hypotenuse]) since a rectangle's diagonals will always cut it into two right triangles:

$13^{2} = 169$

$4^{2} =16$

169-16=153.

$\sqrt{153}$ ≈ 12

or

$\sqrt{153}=12.36931688$

or if the problem has to be exact (using radicals)

3* $\sqrt{17}$

I hope this helps ;)

8 0

2 years ago

91403 divided by 21. Show work

My name is Ann [436]

Answer:

The given Divisor = 21 and Dividend = 91403

43522191403847463110105534211

The Quotient is 4352 and the Remainder is 11

8 0

3 years ago

Read 2 more answers

Urgent! Will award brainliest... Factor the following polynomial: <img src="https://tex.z-dn.net/?f=3a%5E%7B2%7D-21a%2B3

umka2103 [35]

Answer:

$3 (a-2) (a-5)$

Step-by-step explanation:

The first step is to find the GCF. Here, it's 3.

$3(a^2-7a+10)$

Then, you factor the polynomial in the parenthesis.

To find the factors, you will need to find 2 numbers that add to -7, and multiply to 10. -2 and -5 add to -7 and multiply to 10. Now, replace -7a with the factors.

$a^2-2a-5a+10$