Answer:
Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11±
)/2. So, PQ=
, PQ²=
. Thus, the answer is 61+4=65.
Step-by-step explanation:
Answer:
y=-5/6x-5
Step-by-step explanation:
0-(-5)/-6-0
-5/6 slope
y-(-5)=-5/6(x-0)
y+5=-5/6x
y=-5/6x-5
Answer:
B.50.24
8ft is equivalent to 64ft²
Answer:
x = 11
Step-by-step explanation:
If the segments are congruent then
3x = x + 22 ➡ 3x - x = 22
2x = 22 divide both sides by 2
x = 11
Answer:
70x
Step-by-step explanation:
8x8 = 64x then +6x = 70x