Two circles<span> of </span>radius<span> 4 are </span>tangent<span> to the </span>graph<span> of y^</span>2<span> = </span>4x<span> at the </span>point<span> (</span>1<span>, </span>2<span>). ... I know how to </span>find<span> the </span>tangent<span> line from a circle and a given </span>point<span>, but ... </span>2a2=42. a2=8. a=±2√2. Then1−xc=±2√2<span> and </span>2−yc=±2√2. ... 4 from (1,2<span>), so you could </span>find these<span> centers, and from there the</span>equations<span> of the circle
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Answer:
(4,3)
the distance between x1 and x2 then y1 then y2
Answer:
2 and 10
Step-by-step explanation:
Let x be length of the small piece and y the length of the big one.
● y = 5x
Since the big piece is 5 times longer than the short one.
The total length is 12 ft
● y + x = 12
● 5x + x = 12
● 6x = 12
Divide both sides by 6
● 6x/6 = 12/6
● x = 2
So the length of the two pieces are 2 ft and 10 ft (5×2)
