Answer:
1.(1,5) and (2,6) , 6-5/2-1=1/1 m=1 ,y=1x+b
5=1(1)+b 4=b
y=x+4
2.(1,1) and (3,-8) -8-1/3-1=-9/2 m=-9/2 ,y=-9/2x+b
1=-9/2(1)+b b=11/2
y=-9/x+11/2
3.(2.-3) and (5,-2) m=1/3 ,y=1/3x+b
-3=1/3(2)+b -3=2/3+b
-3-2/3=b
b=-11/3
y=1/3x-11/3
4.(2,5)and (4,3) m=-1 y=-1x+b
5=-1(2)+b 5=-2+b
5+2=b
b=7
y=-1x+7
6.(-3,-5) and (-1,-3) m=2/2=1 y=1x+b
-5=1(-3)+b -5=-3+b
-5+3=b
-2=b
y=1x-2
Step-by-step explanation:
Answer:
A) y=1/5x
Step-by-step explanation:
Coz, the way you identify a perpendicular line is by looking for its negative reciprocal. The neagtive reciprocal of 5= 1/5
Now, to check the ans we can multiply the negative reciprocal by "m"
(m in y=mx+c or y=mx+b)
in this case the "m" is stated as 5, so all we need to do is 1/5*5 if the ans is 1 then your ans is right....and over here it is
So thats how you identify & check perpendicular lines!