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2 years ago

3/4^2 + 1^2 = x2 solve for x with work shown! pls help!

Mathematics

2 answers:

photoshop1234 [79]2 years ago

8 0

Answer:

X=19/32

Step-by-step explanation:

3/4^2+1^2=2*x

3/4^2+1=2x

3+(4^2)/4^2=2x

3+16/4^2=2x

19/4^2=2x

19/(2^2)^2=2x

19=16(2x)

19=16*2x

32x=19

32x/32=19/32

x=19/32

This took alot of time goodluck!

Gnom [1K]2 years ago

5 0

Answer: x = ± 5/4

Step-by-step explanation:

x² = 3²/4² + 1

x² = 9/16 + 1

x² = 1·16 + 9/ 16

x² = 25/16

x = √25/16, x = - √25/16

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At a local department store, jeans are typically priced at $15. Due to a special, the jeans are reduced to 80% of their original

vodomira [7]

Answer:the price of jeans now is $12

Step-by-step explanation:

Let x represent the current price of the jeans. At the local department store, jeans are typically priced at $15. It means that the original price of the jeans is $15 .

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x = 15 - (20/100 × 15) = 15 - 3

x = $12

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3 years ago

How to solve x/-3-2=5.5

amid [387]

Okay first set up the equation

x
--- -2 = 5.5
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add over the 2

x
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now you need to multiply the denominator by the answer

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3 years ago

Solve x2 + 4x + 8 = 0. (2 points)

USPshnik [31]

Answer:

x=-4/3

Step-by-step explanation:

7 0

3 years ago

Help me help me help me

Vinil7 [7]

Answer:

40 dollars the answer is 40!!!

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2 years ago

Can I get help solving this graph please?

Daniel [21]

see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0

3 years ago