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RoseWind [281]
1 year ago
7

Write a system of inequalities using the given graph

Mathematics
1 answer:
ch4aika [34]1 year ago
4 0

Take two points

  • (-2,1)
  • (0,-3)

Slope

  • m=-3-1/0+2=-4/2=-2

Parallel lines so slopes are equal

Only y intercept will vary

So both lines have y intercept at -3 and -1 respectively

The equations

  • y=-2x-3
  • y=-2x-1

Put (0,0) on first one

  • 0>-3

On second one

  • 0>-1

So as lines are dashed symbols remain >

The inequalities are

  • y>-2x-3
  • y>-2x-1
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BESTIES PLEASE HELP ASAP WILL GIVE POINTS AND BRAINLIEST. Express as a trinomial (2x-6) (x-4)
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Answer:

2x² - 14x + 24

Step-by-step explanation:

Use the FOIL method (First, Outside, Inside, Last).

First, multiply the first term of both parenthesis:

2x * x = 2x²

Next, multiply the outside terms of both parenthesis:

2x * -4 = -8x

Then, multiply the inside terms of both parenthesis:

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Finally, multiply the last terms of both parenthesis:

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Combine like terms:

2x² - 8x - 6x + 24

2x² (-8x - 6x) + 24

2x² (-14x) + 24

2x² - 14x + 24 is your answer.

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Solve the system of equations by substitution. 3/8 x + 1/3 y =17/24 and <br> x + 7y = 8
goblinko [34]
\left \{ {{ \frac{3}{8}x+ \frac{1}{3}y  = \frac{17}{14} } \atop {x+7y=8}} \right.

To solve this system by substitution, first isolate x in the second equation.

x+7y=8
x+7y-7y=8-7y
x=8-7y

Now, plug this expression (8-7y) for x in the top equation to solve for y.

\frac{3}{8} (8-7y)+ \frac{1}{3} y= \frac{17}{14}
3- \frac{21}{8} y+ \frac{1}{3} y= \frac{17}{24}
72-63y+8y=17
72-55y=17
-55y=17-72
-55y=-55
y=1

Now that you have y, plug it into the second equation and solve for x.

x+7y=8
x+7(1)=8
x+7=8
x=1

Last step is to plug your x- and y-values in to both equations to check your work.

\frac{3}{8} (1)+ \frac{1}{3} y= \frac{17}{24}

\frac{3}{8} * \frac{3}{3} = \frac{9}{24} ;  \frac{1}{3} * \frac{8}{8} = \frac{8}{24}

\frac{9}{24} + \frac{8}{24} = \frac{17}{24}  <--True

1+7(1)=8
1+7=8   <--True

Answer:
x=1 \\ y=1
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3 years ago
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