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3 years ago

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Which table shows a function that is decreasing over the interval (−2, 0)?

2 answers:

zhenek [66]3 years ago

8 0

Answer : Image 3

Which table shows a function that is decreasing over the interval (−2, 0)?

We look at the interval -2 to 0 on x

In option 1 table , f(x) is 0 then -5 and then becomes 0

It means -2 to -1 , f(x) decreases but from -1 to 0 y values increases

In option 2 table , f(x) is increasing from -15 to -5

In option 3 table, f(x) values goes on decreasing over the interval -2 to 0

So , option 3 table shows a function that is decreasing over the interval (−2, 0)

BartSMP [9]3 years ago

5 0

Answer: Table 3 shows that f(x) decreases in the interval (-2,0)

Step-by-step explanation:

Decreasing function: A decreasing function is a function that decreases continuously for a given interval of values

If we see the interval (-2.0) in the first image

the value of f(x) decreases from 0 to -5 and then increases to 0

So it is not decreasing continuously over the interval

For the second image in the interval (-2,0) the value of f(x) increases from -15 to -5 but decreases to -20

So it is also not decreasing continuously for the given interval

For the third image

At x=-2, f(x)= 0

At x=-1, f(x)= -10

At x=0, f(x)=-24

Here the value of f(x) is continuously decreasing over the interval (-2,0)

Hence table 3 shows that the function is decreasing continuously over (-2,0)

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b. The probability is 0.6296

c. The probability is 0

Step-by-step explanation:

If we assume a binomial process, the probability that x customer are willing to switch companies is:

$P(x)=nCx*p^{x}*(1-p)^{n-x}$

nCx is calculated as:

$nCx=\frac{n!}{x!(n-x)!}$

Where n are the 20 cable customers and p is the probability 0.2 that the cable customer are willing to switch companies.

Then, P(x) is:

$P(x)=20Cx*0.2^{x}*(1-0.2)^{20-x}$

The probability that between 2 and 5 (inclusive) customers are willing to switch companies is:

P(2≤x≤5) = P(2) + P(3) + P(4) + P(5)

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$P(3)=20C3*0.2^{3}*(1-0.2)^{20-3}=0.2054$

$P(4)=20C4*0.2^{4}*(1-0.2)^{20-4}=0.2182$

$P(5)=20C5*0.2^{5}*(1-0.2)^{20-5}=0.1745$

So, P(2≤x≤5) is:

P(2≤x≤5) = 0.1369 + 0.2054 + 0.2182 + 0.1745 = 0.735

At the same way, the probability that less than 5 customers are willing to switch is:

P(x<5)=P(0)+P(1)+P(2)+P(3)+P(4)

P(x<5)=0.6296

Finally, the probability that more than 16 customers are willing to switch is:

P(x>16)=P(17)+P(18)+P(19)+P(20)

P(x>16)=0

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