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2 years ago

Can you please graph it? (:

Mathematics

1 answer:

Vika [28.1K]2 years ago

6 0

Graph what? Can you post the equation?

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What is the value of x in the equation 2(6х+4)- 6+ 2х = 3(4х+3) + 12<br> оооо

marissa [1.9K]

Answer:X= 19/2

Step-by-step explanation:

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3 years ago

If 3x−y=12, what is the value of <br>8x<br>--<br>2y

marta [7]

Answer:

wait few minutes i will try

3 0

3 years ago

PLEASE HELP 10 points plus brainliest!

ivann1987 [24]

I think it is b i am not sure

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4 years ago

Hello I need help on this math question

lys-0071 [83]

Answer:

Step-by-step explanation:

3.14(19)=59.7

8 0

2 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

I am Lyosha [343]

I'm pretty sure your answer of 9/2 is correct...

Parameterize $S$ by

$\vec s(u,v)=3v(1-u)\,\vec\imath+3uv\,\vec\jmath+3(1-v)\,\vec k$

with $0\le u\le1$ and $0\le v\le1$ .

In case youre' not sure where this came from: recall the standard parameterization for a line segment connecting two points $\vec p_1$ and $\vec p_2$ ,

$\vec r(u)=(1-u)\vec p_1+u\vec p_2$

with $0\le u\le1$ . Then treating $\vec r(u)$ as a "point", we can parameterize a plane containing $\vec r(u)$ and another point $\vec p_3$ by using

$\vec s(u,v)=(1-v)\vec p_3+u\vec r(u)$

with $0\le v\le 1$ .

Now, take the normal vector to $S$ to be

$\vec r_v\times\vec r_u=9v\,\vec\imath+9v\,\vec\jmath+9v\,\vec k$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^19v(3-3v)\,\mathrm du\,\mathrm dv$

(since the first two components of $\vec F$ cancel in the dot product)

$=\displaystyle27\int_0^1(v-v^2)\,\mathrm dv=\boxed{\frac92}$

4 0

4 years ago