The second one is but i’m so so sure
Answer: 9.8
Step-by-step explanation:
If 7 people paid $3 per ride and road 5 times, it would be $21 dollars. You could do it 3×5=15+7=21
The answer for this problem is
: -7(x^2+4)
Answer:

Step-by-step explanation:
Given △KMN, ABCD is a square where KN=a, MP⊥KN, MP=h.
we have to find the length of AB.
Let the side of square i.e AB is x units.
As ADCB is a square ⇒ ∠CDN=90°⇒∠CDP=90°
⇒ CP||MP||AB
In ΔMNP and ΔCND
∠NCD=∠NMP (∵ corresponding angles)
∠NDC=∠NPM (∵ corresponding angles)
By AA similarity rule, ΔMNP~ΔCND
Also, ΔKAP~ΔKPM by similarity rule as above.
Hence, corresponding sides are in proportion



Adding above two, we get

⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 