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3 years ago

How many lines of symmetry are found in a regular polygon with 80 sides?

Mathematics

1 answer:

IrinaVladis [17]3 years ago

3 0

Answer:

80cause there are 80 sides

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Find the product of (x + 5)(x − 5) and show work

AleksandrR [38]

(x + 5) * (x − 5) =

x² - 25

----------------

x * x = x² and 5 * (-5) = -25

8 0

3 years ago

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Can someone pleaseeeeee help me on this

coldgirl [10]

(5 x 6) + 7 = 37

(5 + 7) x 6 = 72

(6 - 7) / 5 = -1/5

4 0

3 years ago

The sum of the measures of 2 exterior angles is 264°. What is the measure of the third exterior angle?

erma4kov [3.2K]

Well if all angles are suppose to add up to 360 degrees you can the angles to see if the equal up to 360 degrees, 264+96=360.

3 0

3 years ago

Please help!

777dan777 [17]

Answer:

$\begin{array}{ccc}\text{Radius}&\text{Volume of sphere}&\text{Volume of cylinder}\\&&\\1&\dfrac{4}{3}\pi &2\pi \\&&\\2&\dfrac{32}{3}\pi &16\pi \\&&\\3&36\pi &54\pi \\&&\\4&\dfrac{256}{3}\pi &128\pi \\&&\\5&\dfrac{500}{3}\pi &250\pi\end{array}$

Step-by-step explanation:

Use formulas for the volumes:

$V_{sphere}=\dfrac{4}{3}\pi r^3,\\ \\V_{cylinder}=\pi r^2h=\pi r^2\cdot 2r=2\pi r^3.$

1. When r=1,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 1^3=\dfrac{4}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 1^3=2\pi.$

2. When r=2,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 2^3=\dfrac{32}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 2^3=16\pi.$

3. When r=3,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 3^3=36\pi,\\ \\V_{cylinder}=2\pi \cdot 3^3=54\pi.$

4. When r=4,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 4^3=\dfrac{256}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 4^3=128\pi.$

5. When r=5,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 5^3=\dfrac{500}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 5^3=250\pi.$

Note that for all r,

$\dfrac{V_{sphere}}{V_{cylinder}}=\dfrac{\frac{4}{3}\pi r^3}{2\pi r^3}=\dfrac{2}{3}.$

8 0

3 years ago

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What is 7.5% of 180 dollars? please provide step by step answer

Aliun [14]

Answer:

13.5

Step-by-step explanation:

7.5 percent *180=

(7.5:100)*180=

(7.5*180):100=

1350:100= 13.5

5 0

3 years ago

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