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3 years ago

Paraplatin 360mg/m2 in 150ml normal saline via ice pump. Drug run over 30 minutes. At what rate should the nurse at IV pump

1 answer:

7 0

<span>Drag concentration( 360mg) per body surface (m2) is irrelevant to the infusion rate, which is volume divided by time, i.e. 150/(30/60) = 300ml/h</span>

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Y=6x-11<br> -2x-3y=-7 gnjjj

KiRa [710]

Answer:

x=2 y=1

Step-by-step explanation:

Solve the equations by substituting y=6x-11 into -2x-3y=-7.

-2x-3(6x-11)=-7

-2x-18x+33=-7

-20x+33=-7

-20x=-7-33

-20x=-40

x=2

To find y, substitute this value into the equation and solve for y.

y=6(2)-11

y=12-11

y=1

7 0

2 years ago

I need help ASAP . Brainlist will be given !!

dolphi86 [110]

Answer:

5,4 and 4,4

Step-by-step explanation:

3 0

3 years ago

Each side of a square is increasing at a rate of 6 cm/s. at what rate is the area of the square increasing when the area of the

katrin [286]

A = s^2
A' = 2s*s'

When the area is 36 cm^2, the side (s) is 6 cm. The area is increasing at the rate
A' = 2(6 cm)*(6 cm/s) = 72 cm^2/s

8 0

3 years ago

Solve the following initial-value problem, showing all work, including a clear general solution as well as the particular soluti

Vikki [24]

Answer:

General Solution is $y=x^{3}+cx^{2}$ and the particular solution is $y=x^{3}-\frac{1}{2}x^{2}$

Step-by-step explanation:

$x\frac{\mathrm{dy} }{\mathrm{d} x}=x^{3}+3y\\\\Rearranging \\\\x\frac{\mathrm{dy} }{\mathrm{d} x}-3y=x^{3}\\\\\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{3y}{x}=x^{2}$

This is a linear diffrential equation of type

$\frac{\mathrm{d} y}{\mathrm{d} x}+p(x)y=q(x)$ ..................(i)

here $p(x)=\frac{-2}{x}$

$q(x)=x^{2}$

The solution of equation i is given by

$y\times e^{\int p(x)dx}=\int e^{\int p(x)dx}\times q(x)dx$

we have $e^{\int p(x)dx}=e^{\int \frac{-2}{x}dx}\\\\e^{\int \frac{-2}{x}dx}=e^{-2ln(x)}\\\\=e^{ln(x^{-2})}\\\\=\frac{1}{x^{2} } \\\\\because e^{ln(f(x))}=f(x)]\\\\Thus\\\\e^{\int p(x)dx}=\frac{1}{x^{2}}$