Answer:
(6, -3)
Step-by-step explanation:
The actual coordinates are x = -6 and y = 3
If we rotate 180 degrees and the center of rotation is at (0,0), all we need to do is invert the signal of each axis, that is, we invert the sign of the original x-coordinate and invert the signal of the original y-coordinate.
So the final x-coordinate is - (-6) = 6
And the final y-coordinate is - (3) = -3
So the coordinates will be (6, -3).
Answer: it means to make larger or smaller.
Step-by-step explanation:
it means to make larger or smaller.
Answer:
-(x+2)/(x+8)
Step-by-step explanation:
( x^2 -x-6)
------------------
24 - 5x -x^2
Factor out a minus sign from the denominator
( x^2 -x-6)
------------------
-( x^2 +5x -24)
Factor the numerators and the denominators
( x-3) (x+2)
------------------
-( x+8)(x-3)
Cancel like terms
x+2
------------------
-(x+8)
Since there are as many of these triangles as the polygon has sides (eight for an octagon), you have to multiply the area of this triangle by the number of sides. You will obtain the total area of the octagon: area of octagon = 8 * base * height / 2 = perimeter * apothem / 2 .
i hope this helped you :)
1.b)
Fred has F cards. Bill has B cards. Tim has T cards.
B + F + T = 167
B = 5F
T = 4F - 3
5F + F + 4F - 3 = 167
10F - 3 = 167
10F = 170
F = 17
Fred has 17 cards.
B = 5F = 5(17) = 85
Bill has 85 cards.
T = 4F - 3 = 4(17) - 3 = 65
Tim has 65 cards.
2.a)
length = L
width = W
L = W + 5
perimeter = 2L + 2W = 168
2L + 2W = 168
2(W + 5) + 2W = 168
2W + 10 + 2W = 168
4W = 158
W = 39.5
L = W + 5 = 39.5 + 5 = 44.5
Length = 44.5 inches
Width = 39.5 inches
2.b)
Original rectangle:
width = W
length = 2W
New rectangle:
width = W - 1
length = 2W + 4
perimeter = 198 inches
perimeter = 2L + 2W = 198
2(2W + 4) + 2(W - 1) = 198
4W + 8 + 2W - 2 = 198
6W + 6 = 198
6W = 192
W = 32
L = 2W = 64
width = 32 inches
length = 64 inches
3.a)
Now:
Sam's age = S
John's age = 3S
In 5 years:
John's age = 3S + 5
Sam's age = S + 5
3S + 5 = 2(S + 5)
3S + 5 = 2S + 10
S = 5
Sam's age is 5.
John's age is 15.
This is all I have time for now. Post the rest of the problems in a different post, and I'll try to help later.
