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antiseptic1488 [7]
3 years ago
15

What role does gravity and inertia play in our Solar System?

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
3 0
It keeps the planets in orbit.

Inertia is what keeps an object moving (in the same direction). Gravity is the pull of an object to another.

The planets have reached the perfect medium to where inertia keeps the planets moving (instead of remaining completely still in space), and gravity pulls them toward the sun so that they move around it instead of moving straight past it or straight into it.

This is also true about the Earth and the moon.

This is also true with satellites in orbit.
You might be interested in
Please help and show work
Bogdan [553]
The answer should be X= 3.60m
3 0
3 years ago
Is this a <br> A) Acute<br> B)Equiangular<br> C)obtuse<br> D)right
vampirchik [111]

The answer is A) Acute


8 0
3 years ago
Read 2 more answers
The volumes of two spheres are in a ratio of 1:8 what is the eatio rafi
Agata [3.3K]
Remark
I take it that you want to know the ratio of the radii. If this is not correct, leave a comment below my answer.

You could do this by giving the spheres a definite volume, like 1 and 8 and then solve for r for one of them and then use the other sphere to find it's radius. It is not exactly the best way, and if you are going to to a physics class you want to be doing this using cancellation. 

Step One 
Set up the Ratio for the volumes.

\frac{V_1}{V_2} =  \frac{1}{8}

Step Two
Setup the equation for V1/V2 using the definition for a sphere. V = 4/3 pi r^3

\dfrac{1}{8} =  \frac{ \frac{4}{3} \pi( r_1)^3 }{ \frac{4}{3} \pi( r_2)^3 }

Step Three
Cancel the 4/3 and pi on the top and bottom of the fractions on the right.

You are left with 1/8 = (r1)^3/ (r2)^3

Step Four
Take the cube root of both sides.
cube root 1/8 = 1/2

Cube root of (r1)^3 = r1
Cube root of (r2)^3 = r2

Step  Five
Answer
\frac{r_1}{r_2} =  \frac{1}{2}   Answer <<<<<<<
8 0
3 years ago
Factor-3/4 out of 3/2x-9/4y
S_A_V [24]

For this case we must factor - \frac {3} {4}of the following expression:

\frac {3} {2} x- \frac {9} {4}y

By law of signs of multiplication it is fulfilled that:

- * - = +\\- * + = -

So we have to:

- \frac {3} {4} * (- 2) = + \frac {6} {4} = + \frac {3} {2}\\- \frac {3} {4} * 3 = - \frac {9} {4}

Thus, by factoring we have:

- \frac {3} {4} (- 2x + 3y)

Answer:

- \frac {3} {4} (- 2x + 3y)

5 0
3 years ago
I need help for both of these !
VLD [36.1K]
4. \frac{w+3}{2}<-8
First, you can multiply both sides of the inequality by 2 to cancel out the fraction to get:
w+3<-16
Then subtract 3 from both sides to get:
w<-19 
Above is your answer

5. h≤\frac{6h+3}{5} 
Like we did in the first one, multiply by 5 on both sides to get: 
5h≤6h+3
Then subtract 6h from both sides to get
-1h≤3
Divide by -1 into both sides, and when you divide or multiply an inequality by a negative number, you flip the sign, so you would get
h≥-3
Above is your final answer

Hope this helped!
6 0
3 years ago
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