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harkovskaia [24]
3 years ago
11

What is the inequality

Mathematics
1 answer:
Nutka1998 [239]3 years ago
4 0

Answer:

x ≥ 4

Step-by-step explanation:

Well to find the inequality we need to single out x,

4x - 1 ≥ 15

+1 to both sides

4x ≥ 16

Divide 4 by both sides

x ≥ 4

<em>Thus,</em>

<em>x is greater than or equal to 4.</em>

<em />

<em>Hope this helps :)</em>

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Jon earns $4 for delivering groceries and $2 for each delivery he makes.
asambeis [7]

Answer:

$14

Step-by-step explanation:

ok so since he is delivering groceries he gets $4.

now when he delivers he get $2 more, so for each house he delivers to he adds $2 to that $4.

so the easiest was to do this is 5x2.

5x2 is 10.

now $10 is how much more he gets on top of the $4, so now we need to add the $4 to the $10.

your answer is $14  

plz mark brainliest!

8 0
3 years ago
F(x)=8x +5, which function represents f(e-9)
Ronch [10]

Answer:

f(e - 9) = 8e - 67

Step-by-step explanation:

To evaluate f(e - 9) substitute x = e - 9 into f(x)

f(e - 9) = 8(e - 9) + 5 = 8e - 72 + 5 = 8e - 67

7 0
3 years ago
Mary makes trail mix with bulk nuts and dried fruit. She spends $4.50 on the dried fruit. Mixed nuts cost $2.50 per pound. She h
AnnyKZ [126]

Answer: 3 pounds

Step-by-step explanation: 12 - 4.50 = 7.50 7.50/2.50=3

4 0
3 years ago
HELP! A daycare purchases two type of snacks, granola bars and fruit rolls. One week, they purchase 10 packs of granola bars and
ch4aika [34]
10x+6y=152
5x+3y=76
7x+12y=200
-20x-12y=-304
-13x=-104
x=8
40+3y=76
3y=36
y=12
There are 8 granola bars in a pack and 12 fruit rolls in a pack
5 0
3 years ago
Read 2 more answers
A football quarterback enjoys practicing his long passes over 40 yards. He misses the first pass 40% of the time. When he misses
laila [671]

Answer:

Probability of missing two passes in a row is 0.08.

Step-by-step explanation:

Event E = A football player misses twice in a row.

P(E) = ?

Event X = Football player misses the first pass

P(X) = 0.4

Event Y = Football player misses just after he first miss

P(Y) = 0.2

Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:

P(E) = P(X).P(Y)

P(E) = 0.4*0.2

P(E) = 0.08

4 0
3 years ago
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