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2 years ago

About how many people had viewed the video once it had been online for 20 days? 190 858 6,271 86,460

SAT

1 answer:

aev [14]2 years ago

4 0

About 6,271 people had viewed the video once it had been online for 20 days. The correct option is C.

<h3>What is exponential equation?</h3>

Exponential equation is the equation in which the exponent or part of exponents used as variables.

$fx = 33 \times (1.3)^x$

where, x is the number of days, given that x = 20

Putting the values in the equation

$f\times 20 = 33 \times (1.3)^2^0 = 6,271 \;days$

Thus, the correct option is C, 6,271.

Learn more about exponential equation

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the height of a bottle rocket, in meters, is given by the function s(t)=−9t2+103t+403. find the average velocity of the bottle r

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The average velocity of the bottle rocket are two given time intervals is 30 m/s and 20 m/s respectively, while the instantaneous velocity at 4.5 seconds is 22 m/s.

The given parameters;

s(t) = -9t² + 103t + 403
time interval (4.499, 4.5), and (4.5, 4.501)

The average velocity of the bottle rocket over the intervals is calculated as follows;

when the interval = [<em>4.499, 4.5</em>]

$s(4.499)= -9(4.499)^2 + 103(4.499) + 403 = 684.22 \ m\\\\s(4.5) = -9(4.5)^2 + 103(4.5) + 403 = 684.25 \ m$

$v = \frac{\Delta \ s}{\Delta \ t} = \frac{684.25 - 684.22}{4.5 - 4.499} = 30 \ m/s$

when the interval = [<em>4.5, 4.501</em>]

$s(4.5) = -9(4.5)^2 + 103(4.5) + 403 = 684.25 \ m\\\\s(4.501) = -9(4.501)^2 + 103(4.501) + 403 =684.27 \ m\\\\v= \frac{684.27 - 684.25}{4.501-4.5} \\\\v = 20 \ m/s$

The instantaneous velocity of the bottle rocket at time t=4.5;

$v = \frac{d \ s(t)}{dt} = -18t + 103\\\\v(4.5) = -18(4.5) + 103\\\\v(4.5) = 22 \ m/s$

Thus, the average velocity of the bottle rocket are two given time intervals is 30 m/s and 20 m/s respectively, while the instantaneous velocity at 4.5 seconds is 22 m/s.

Learn more here: brainly.com/question/25009886

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