Answer:
x = (-105300)/23
Step-by-step explanation:
Solve for x:
5 x + 526500/23 = 0
Hint: | Put the fractions in 5 x + 526500/23 over a common denominator.
Put each term in 5 x + 526500/23 over the common denominator 23: 5 x + 526500/23 = (115 x)/23 + 526500/23:
(115 x)/23 + 526500/23 = 0
Hint: | Combine (115 x)/23 + 526500/23 into a single fraction.
(115 x)/23 + 526500/23 = (115 x + 526500)/23:
(115 x + 526500)/23 = 0
Hint: | Multiply both sides by a constant to simplify the equation.
Multiply both sides of (115 x + 526500)/23 = 0 by 23:
(23 (115 x + 526500))/23 = 23×0
Hint: | Cancel common terms in the numerator and denominator of (23 (115 x + 526500))/23.
(23 (115 x + 526500))/23 = 23/23×(115 x + 526500) = 115 x + 526500:
115 x + 526500 = 23×0
Hint: | Any number times zero is zero.
0×23 = 0:
115 x + 526500 = 0
Hint: | Isolate terms with x to the left hand side.
Subtract 526500 from both sides:
115 x + (526500 - 526500) = -526500
Hint: | Look for the difference of two identical terms.
526500 - 526500 = 0:
115 x = -526500
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of 115 x = -526500 by 115:
(115 x)/115 = (-526500)/115
Hint: | Any nonzero number divided by itself is one.
115/115 = 1:
x = (-526500)/115
Hint: | In (-526500)/115, the numbers 526500 in the numerator and 115 in the denominator have gcd greater than one.
The gcd of 526500 and 115 is 5, so (-526500)/115 = (-(5×105300))/(5×23) = 5/5×(-105300)/23 = (-105300)/23:
Answer: x = (-105300)/23
