A. the first box is 7
the second box is 2
the third box is 100
the fourth box is 6.5
RULE: times 3 + 2
b. the first box is 45/2
the second box is -0.75
the third box is 0
the fourth box is 2.75
RULE: times 5/2
c. the first box is 1 1/2
the second box is 6
the third box is -4
the fourth box is -1.75
RULE: times half add one
Since you don't want any leftover items, you have to find the greatest common factor (GCF) of both the crayons and bubbles. Since the highest common factor for both 28 and 12 is 4, the greatest number of gift bags you can make without any leftover items would be 4 gift bags.
Hope I could help.
Answer:
(a) If r is any rational number and s is any irrational number, then r/s is rational
(b) The statement is false when r is 0
Step-by-step explanation:
Given
rational number
irrational number
irrational number
Solving (a): The negation
To get the negation of a statement, we only need to negate the end result
In other words, the number type of r and s will remain the same, but r/s will be negated.
So, the negation is:
rational number
irrational number
rational number
Solving (b): When r/s is irrational is false
Given that:
irrational number
Set r to 0
So:
-- rational
<em>Hence, the statement is false when r is 0</em>
4/5x - 4/10 = 2/20...multiply everything by common denominator 20
16x - 8 = 2
16x = 2 + 8
16x = 10
x = 10/16 which reduces to 5/8 <=
Answer:
Step-by-step explanation:
