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Ad libitum [116K]
2 years ago
14

The hypotenuse of a right triangle measures 4 cm and one of its legs measures 3 cm. Find the measure of the other leg. If necess

ary, round to the nearest tenth.
Mathematics
1 answer:
hodyreva [135]2 years ago
4 0

Applying the Pythagorean theorem, the measure of the other leg, to the nearest tenth, is: 2.6 cm.

<h3>What is the Pythagorean Theorem?</h3>

In a right triangle, where the lengths of its two legs are a and b, and the hypotenuse length is c, the Pythagorean theorem states that: c² = a² + b².

Given the following parameters of the right triangle:

  • c = 4 cm
  • a = 3 cm
  • b = ? (other leg)

Apply the Pythagorean theorem:

b = √(4² - 3²)

b = 2.6 cm (nearest tenth)

Thus, applying the Pythagorean theorem, the measure of the other leg, to the nearest tenth, is: 2.6 cm.

Learn more about Pythagorean theorem on:

brainly.com/question/654982

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Consider the given right triangle. If angle B = 43 degrees and c = 26.7 meters, find a.
Nady [450]

Answer: Side a equals 19.5 metres

Step-by-step explanation: Consider the right angled triangle as shown in the picture attached. The triangle has been drawn with angle measuring 43 degrees, side c (line AB) measuring 26.7 m and side a (line CB) is yet unknown.

A right angled triangle can be solved if at least one side and an angle are available. In this question we shall apply the trigonometric ratios since we have one angle which shall be the reference angle (43°). Also we have an hypotenuse (the side facing the right angle) and an unknown side which is the adjacent (which lies between the right angle and the reference angle).

Cos B = Adjacent/Hypotenuse

Cos 43 = a/26.7

Cos 43 x 26.7 = a

0.7314 x 26.7 = a

19.52714 = a

a ≈ 19.5  (rounded to the nearest tenth)

Therefore the length of side a equals 19.5 metres.

3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx....%7D%20%7D%20%7D%20%7D%20%20%3D%20%
andrey2020 [161]

First observe that if a+b>0,

(a + b)^2 = a^2 + 2ab + b^2 \\\\ \implies a + b = \sqrt{a^2 + 2ab + b^2} = \sqrt{a^2 + ab + b(a + b)} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{\cdots}}}}

Let a=0 and b=x. It follows that

a+b = x = \sqrt{x \sqrt{x \sqrt{x \sqrt{\cdots}}}}

Now let b=1, so a^2+a=4x. Solving for a,

a^2 + a - 4x = 0 \implies a = \dfrac{-1 + \sqrt{1+16x}}2

which means

a+b = \dfrac{1 + \sqrt{1+16x}}2 = \sqrt{4x + \sqrt{4x + \sqrt{4x + \sqrt{\cdots}}}}

Now solve for x.

x = \dfrac{1 + \sqrt{1 + 16x}}2 \\\\ 2x = 1 + \sqrt{1 + 16x} \\\\ 2x - 1 = \sqrt{1 + 16x} \\\\ (2x-1)^2 = \left(\sqrt{1 + 16x}\right)^2

(note that we assume 2x-1\ge0)

4x^2 - 4x + 1 = 1 + 16x \\\\ 4x^2 - 20x = 0 \\\\ 4x (x - 5) = 0 \\\\ 4x = 0 \text{ or } x - 5 = 0 \\\\ \implies x = 0 \text{ or } \boxed{x = 5}

(we omit x=0 since 2\cdot0-1=-1\ge0 is not true)

3 0
1 year ago
Can someone please help me? I'm desperate lol
ddd [48]

Answer:

y = 3

Step-by-step explanation:

Since the equation is parallel to the x-axis, it is a horizontal line, which means it has a slope of 0. Since anything times 0 is 0, that means x times 0 is 0, so we can take that out of the equation. That only leaves the y-intercept, which is 3. Substituting it into the equation, we get y = 3.

Hope this helps!

If you still don't understand or need help, send a comment or message.

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3 years ago
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A rectangle with vertices L(3, –1), M(3, –8), N(8, –8), and O(8, –1) is reflected over the y-axis.
Katen [24]

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Use the drop down menu to select what each number indicates about the data points.​
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Answer: median:3

Mean:4

Mode:2

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