All categories

2 years ago

Find the domain of f(x) = 3x for the range {-7, -1, 3, 11}. =

Mathematics

1 answer:

Sergeeva-Olga [200]2 years ago

3 0

Answer: i dont know

Step-by-step explanation:

You might be interested in

Can someone please help me on this problem?

nekit [7.7K]

Answer:

$5820.07

Step-by-step explanation:

Substitute 243 into the equation for n:

$c=117\sqrt[3]{243^{2} }+1264\\c=117\sqrt[3]{59049}+1264\\c=117*38.9407384+1264\\c=4556.06639+1264\\c=5820.06639$

Round 5820.06639 to the nearest hundredth:

5820.07

$5820.07

3 0

2 years ago

The equation y=10(1.0605)^x represents the winning prize money, in thousands, for first place in the Indianapolis 500 auto race.

Andreas93 [3]

Using the value of x = 50 and putting it into the equation:

y = 10 x (1.0605)⁵⁰
y = 188.6

The winning prize money in 1961 is 188.6 thousand dollars.

7 0

3 years ago

Read 2 more answers

How to round 94000.00 two decimal places

swat32

Answer:

94000.00 is already in two decimal places.

Step-by-step explanation:

Every number after the decimal point represent a place in decimal.

One Decimal place = .0

Two Decimal place = .00

Three Decimal place = .000

Four Decimal place = .0000

3 0

3 years ago

Write an inequality to model the situation.

svet-max [94.6K]

Answer:

$n >21$

Step-by-step explanation:

The number exceeds 21 or is greater than 21.

‘ $>$ ’ represents greater than.

Let the number be $n$ .

$n >21$

8 0

2 years ago

Read 2 more answers

I really don’t understand this and just need an explanation of how to do it.

sertanlavr [38]

$\bf ~\hspace{12em}\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\cfrac{2n}{-3n\cdot -2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{-2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n\cdot -n}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n}\cdot \cfrac{1}{-n}$

$\bf \cfrac{1}{-3n}\cdot \boxed{1}\cdot \cfrac{1}{-n}\implies \cfrac{1}{-3n\cdot -n}\implies \cfrac{1}{3n^2}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4\implies \left( \cfrac{1}{3n^2} \right)^4\implies \stackrel{\textit{distributing the exponent}}{\cfrac{1^4}{3^4n^{2\cdot 4}}}\implies \cfrac{1}{81n^8}$

7 0

2 years ago