What would the distance be of a crater of 4300 feet in diameter use 3.14 pi\

1 answer:

4 0

Answer : 13502 ft
Circumference of crater 2 pi r
Diameter = 4300
Radius = (4300/2)
Distance = 2 × 3.14 × (4300/2)
= 13502 ft

Hope it helped!

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Find the midpoint of the segment with given endpoints k(1.7,-7.9) and l(8.5,-8.2)

zhenek [66]

I think it would be 5.2

6 0

3 years ago

Urgent, please i will give brainliest

Ne4ueva [31]

Answer:

1. $\frac{\sqrt{13} }{3}$

2. 3.2362

3. $\frac{60}{11}$

Step-by-step explanation:

Cot is the trigonometric ratio defined by "adjacent" over "opposite". So, adjacent = 2 and opposite = 3.

By pythagorean theorem, we have the "hypotenuse" as $\sqrt{2^2+3^2}=\sqrt{13}$

Csc is defined as the trig ratio "hypotenuse" over "opposite". We know the sides, so Csc $\theta$ = $\frac{\sqrt{13} }{3}$

First answer choice is right.

By definition, Csc $\theta$ is the inverse of Sine $\theta$ . If given the value of sin theta, to find value of csc theta, we take the reciprocal of it. Hence:

$Csc\theta=\frac{1}{0.3090}\\=3.2362$

Third answer choice is right.

By definition tan and cot are inverse of each other. So the value of tan is the reciprocal of the value of cot. We can simply "flip" the value of tan theta to get the value of cot theta. Hence:

$Cot\theta=\frac{60}{11}$