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notka56 [123]
3 years ago
12

Two consecutive angles of a parallelogram are always

Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0

Answer:

b

Step-by-step explanation:

in a parallelogram consecutive angles sum to 180°

This means that consecutive angles are supplementary

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One card is drawn from a well shuffled deck of 52 cards find the probability of getting a red 10
Julli [10]
The probability of getting a red card is 1/2 and the probability of getting a 10 is 4/52. To find the probability of getting both a red card and a 10, multiply the two.

(1/2)(4/52) = 4/104
4/104 = 1/26

Therefore, the probability is 1/26
7 0
3 years ago
A rectangle has an AREA of 36in2​ and the height measures 9 in. What is the base measurement?
RSB [31]
Area =bh
36in2=b(9)
——— ——
9 9

36
—— =4
9

Base= 4
7 0
3 years ago
The product of two negative integers is 36. The second integer is 5 more than the first. Find the integers.
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-13 -23 because divide by two then add five and subtract 5
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Consider the function f(x)=2|x|-3. What is f(-3)?
olganol [36]

f(-3)=2|-3|-3=6-3=3\\f(-3)=3

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8 0
4 years ago
A dog chases a squirrel. The dog is originally 200 feet away from the squirrel. The dog's speed is 150 feet per minute. The squi
Dafna11 [192]

Answer:

15 seconds

Step-by-step explanation:

If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy:  the dog's rate is 150 and the squirrel's is 100.  The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know:  the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up.  Since we don't know what d is, we will just call it d!  Now it seems as though we have 2 unknowns which is a problem.  However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other.  Here's the dog's equation:

d = rt

d+200 = 150t

And the squirrel's:

d = 100t

If we solve both for t and set them equal to each other we have:

\frac{150}{d+200} =\frac{100}{d}

Now we can cross multiply to solve for d:

150d = 100d + 20,000 and

50d = 20,000

d = 400

But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took.  So sub that d value back into one of the equations we have solved for t and do the math:

t=\frac{100}{d}=\frac{100}{400} =\frac{1}{4}

That's 1/4 of a minute which is 15 seconds.

6 0
4 years ago
Read 2 more answers
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