Answer: 68
Explanation:
Let x be the age of Mr Jasmi
y be the age of Miss Haslinda
a + b + c be the age of the 3 children
We can write:
(x + y + a + b + c)/5 = 38
But:
(a + b + c)/3 = 18
a + b + c = 18(3)
a + b + c = 54
Substitute this value to our first equation
(x + y + 54)/5 = 38
x + y + 54 = 38(5)
x + y + 54 = 190
x + y = 190 - 54
x + y = 136
Thus:
Mean age of (mr jasmi and miss Linda) = (x+y)/2
But x + y = 136
=> mean age = 136/2 = 68
Answer:
(8,8)
Step-by-step explanation:
(2,2)
(x1+x2)/2, (y1-y2)/2
(-2+6)/2=(2)
(-2+6)/2=2
Rectangle: a = w x l
Square: a = a^2
Triangle: a= b x h divided by 2
Parallelogram: a = HH
Trapezoid: a = a+b
2h
Answer:
2/6
Step-by-step explanation:
1/3 times 2
