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Musya8 [376]
3 years ago
10

The production function f(x) gives the number of units of an item that a manufacturing com pany can produce from units of raw ma

terial. The company buys the raw material at price w dollars per unit and sells all it produces at a price of p dollars per unit. The quantity of raw material that maximizes profit is denoted by x*.
(a) Do you expect the derivative f'(x) to be positive or negative? Justify your answer

(b) Explain why the formula π(x) = pf(x) - wx gives the profit π(x) that the company earns as a function of the quantity x of raw materials that it uses.

(c) Evaluate f'(x*).
Mathematics
1 answer:
makvit [3.9K]3 years ago
5 0

Answer:

Step-by-step explanation:

Recall that the notion of the derivative of a function is the rate of change of it. So it kind of tells us how much the value of functioin changes as the independt variable increases or decreases. If it is positive, this means that the function will increase as the indepent variable increases, and if it is negative, that means that the function will decrease as the indepent variable increases.

a) Since f(x) is the number of units you can make out of x units of raw material, it is natural to think that the more material you have, the more units you can make, so we expect f'(x) to be positive.

b) The company buys each unit of raw material at the price w. So the product wx represents the total cost of the raw material used to produce f(x) units. Since each produced unit is sell at the price of p, then the product pf(x) represents the total income for selling all f(x) units.Recall that the profit is the difference between the total income and the total cost of production. Hence, the profit in this case is represented by the formula pf(x)-wx.

c) Recall that a function h(x) that is differentiable attains it's maximum when it's derivative is 0 and it's second derivative is negative.

In this case, we know that the derivative of the profit function, evaluated at x* must be 0, since it is a maximum. So, using the rules of derivation, we know that the derivative of the profit function is pf'(x)-w. Hence,

pf'(x*)-w =0. From where we know that f'(x*)=w/p.

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postnew [5]

Answer:

  48 kg

Step-by-step explanation:

The given relations can be used to write a system of equations for the two weights. Those can be solved to find Jane's weight.

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<h3>setup</h3>

Let x and y represent Jane's and Jessica's original weight, respectively. The ratio of weights was ...

  x/y = 8/9

After the changes in weight, they were equal:

  x+2 = y-4

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<h3>solution</h3>

Adding 4 to the second equation, we have an expression for y that can be substituted into the first equation.

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Jane weighed 48 kg at first.

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<em>Alternate solution</em>

The original difference in "ratio units" was 9-8 = 1 ratio unit. We find that this corresponds to 6 kg after the weight changes make the weights equal. Then 8 ratio units will be 8(6 kg) = 48 kg—Jane's original weight.

(This mental solution is virtually the same as the solution using equations shown above.)

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If you were 2 years old in 2011 how old would you be in 2020?
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Answer:

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Step-by-step explanation:

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also meaning they were born in 2009

2020-2009 also equals 11

this prolly doesnt make sense but hope it helps :) <3

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Answer:

Step-by-step explanation:

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