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3 years ago

The value of x in 6x+7=3x+16

Mathematics

2 answers:

kozerog [31]3 years ago

4 0

Answer:

x=3

Step-by-step explanation:

6x+7=3x+16

Subtract 3x from each side

6x-3x+7=3x-3x+16

3x+7 = 16

Subtract 7 from each side

3x+7-7 = 16-7

3x =9

Divide each side by 3

3x/3 = 9/3

x =3

slavikrds [6]3 years ago

3 0

Step-by-step explanation:

$6x + 7 = 3x + 16$

First, let's move all of the terms with an $x$ to the left-hand side of the equation, and everything else to the right-hand side of the equation:

$6x - 3x = 16 - 7$

$3x = 9$

Now, let's divide both sides by $3$ to isolate the $x$ on the left-hand side:

$\frac{3x}{3} = \frac{9}{3}$

$x = 3$

Therefore, the value of $x$ in the above equation is $3$ .

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Given cos theta = - 2/5 and sin theta < 0, find the six trigonometric values. I need help with this

Lena [83]

Answer:

$\sin\,\theta =-\frac{\sqrt{21} }{5}$

$\tan\,\theta =\frac{\sqrt{21} }{2}$

$\sec\,\theta = \frac{-5}{2}$

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$\cot\,\theta =\frac{2}{\sqrt{21} }$

Step-by-step explanation:

$\cos\theta =\frac{-2}{5}$

As both $sin\,\theta$ ,

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In the third quadrant,

$\sin\theta$

$\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}$

$\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}$

$\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}$

$\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }$

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3 years ago

How do you write 70,000,000+400,000+10,000+8,000+500+30+9 in word form

alina1380 [7]

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Lady_Fox [76]

Answer:

Step-by-step explanation:

The coefficient is the number that comes before the variable

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Hope this helps! :)

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A man earned x pesos in 10 days and spent y pesos during each of those days. Write an expression to determine how many pesos he

Vsevolod [243]

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gogolik [260]

Answer:

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