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Alchen [17]
2 years ago
13

PLSSS HELP IF YOU TURLY KNOW THISS

Mathematics
2 answers:
Veseljchak [2.6K]2 years ago
3 0

Answer:

i

Step-by-step explanation:

each "|" represents 0.1 so you count to the 6th onee

Olenka [21]2 years ago
3 0

Answer:

The answer is I because it is 4 away from the one so it is not a whole which makes it 0.6.

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The speed limit on a road in Canada is 70 kilometers per hour. What is this speed in miles per hour?
Lera25 [3.4K]

Answer:

43.496

Step-by-step explanation:

When going from kilometers to miles, divide the length in kilometers by 1.609. When we do that, we get 43.496.

6 0
3 years ago
If BE=9cm, find GE<br> What is the answer
Sladkaya [172]

Answer:

GE = 3 cm

Step-by-step explanation:

BE = 9 cm

Since G is the centroid, therefore:

GE = \frac{1}{3}(BE) => Centroid theorem

Plug in the value

GE = \frac{1}{3}(9)

GE = 3 cm

6 0
3 years ago
Solve for x <br><br> 2x^2 - 8x + 5 = 0<br><br> x= ____ or x= ______
lisov135 [29]
\left[x _{2}\right] = \left[ 2+\frac{\sqrt{6}}{2}\right][x​2​​]=[2+​2​​√​6​​​​​] this is answer
7 0
4 years ago
Read 2 more answers
please help!! Assume the given triangular prism and rectangular prism have equal cross sections. Also assume the length and widt
ehidna [41]
Well the difference in the triangle and rectangle prism is  that the equation called for 1/2 of the triangles b times h but the rectangle doesn't get divided by two so if the cross sections are equal the for the rectangle it would be v= 50(2)
of v=100
3 0
3 years ago
Read 2 more answers
A line segment AB has the coordinates A (2,3) AND B ( 8,11) answer the following questions (1) What is the slope of AB? (2) What
GalinKa [24]

Answer:

(1) The slope of the line segment AB is 1.\bar 3

(2) The length of the line segment AB is 10

(3) The coordinates of the midpoint of AB is (5, 7)

(4) The slope of a line perpendicular to the line AB is-0.75

Step-by-step explanation:

The coordinates of the line segment AB are;

A(2, 3) and B(8, 11)

(1) The slope of a line segment is given by the following equation;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Where;

(x₁, y₁) and (x₂, y₂) are two points on the line segment

Therefore;

The slope, m, of the line segment AB is given as follows;

A(2, 3) = (x₁, y₁) and B(8, 11) = (x₂, y₂)

Slope, \, m_{AB} =\dfrac{11-3}{8-2} = \dfrac{8}{6}  = 1 \frac{1}{3} = 1.\bar3

The slope of the line segment AB = 1.\bar 3

(2) The length, l, of the line segment AB is given by the following equation;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Therefore, we have;

l_{AB} = \sqrt{\left (11-3  \right )^{2}+\left (8-2  \right )^{2}} = \sqrt{64 +36} = 10

The length of the line segment AB is 10

(3) The coordinates of the midpoint of AB is given as follows;

Midpoint, M = \left (\dfrac{x_1 + x_2}{2} , \ \dfrac{y_1 + y_2}{2} \right )

Therefore;

Midpoint, M_{AB} = \left (\dfrac{2 + 8}{2} , \ \dfrac{3 + 11}{2} \right ) = (5, \ 7)

The coordinates of the midpoint of AB is (5, 7)

(4) The relationship between the slope, m₁, of a line AB perpendicular to another line DE with slope m₂, is given as follows;

m_1 = -\dfrac{1}{m_2}

Therefore, the slope, m₁, of the line perpendicular to the line AB, that has a slope m₂ = 4/3 = 1.\bar 3 is given as follows;

m_1 = -\left (\dfrac{1}{\frac{4}{3} } \right ) = -\dfrac{3}{4}  = -0.75

The slope, m₁, of the line perpendicular to the line AB is m₁ = -0.75.

8 0
3 years ago
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