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maxonik [38]
3 years ago
10

Give (in percents) the two marginal distributions, for marital status and for income. Do each of your two sets of percents add t

o exactly 100%? If not, why not?

Mathematics
2 answers:
PolarNik [594]3 years ago
5 0

Answer:

Answer is attached

Step-by-step explanation:

6.11

Marginal Distribution of Marital Status

Single 4.1%

Married 93.9%

Divorced 1.5%

Widowed .5%

Marginal Distribution of Job Grade

Job Grade 1 11.6%

Job Grade 2 51.5%

Job Grade 3 30.2%

Job Grade 4 6.7%

Each of the marginal distributions sum up to exactly 100%. Depending on how one rounds the percentages, it is possible that the results will not be exactly 100%.

In-s [12.5K]3 years ago
3 0

Answer:

Step-by-step explanation:

Anwers are in the following attachments.

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PLEASE HELP!!
Stolb23 [73]

Answer:

27 quarters and 37 nickels

Step-by-step explanation:

Nickels are 5¢

Quarters are 25¢

$8.60 is 172 nickels (860/5)

$8.60 is 34.4 quarters (860/25)

So then let's split it half-and-half.

425 and 435

425 would become 17 quarters.

435 would become 87 nickels.

This is still too much.

Now let's try 700 and 160.

700 would become 28 quarters

160 would become 32 nickels.

28+32=60.

This is a lot closer.

So now 27 quarters and 37 nickels. This works.

7 0
2 years ago
I need help with this, I don't understand this
Rudiy27
If you are trying to find the plot you go up as meany numbers as it says and then go over as meany numbers as it says.
8 0
3 years ago
Mopeds (small motorcycles with an engine capacity below 50 cm3) are very popular in Europe because of their mobility, ease of op
Mashcka [7]

Answer:

a) P(X<50)=0.9827

b) P(X>47)=0.4321

c) P(-1.5<z<1.5)=0.8664

Step-by-step explanation:

We will calculate the probability based on a random sample of one moped out of the population, normally distributed with mean 46.7 and standard deviation 1.75.

a) This means we have to calculate P(x<50).

We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

z=\dfrac{X-\mu}{\sigma}=\dfrac{50-46.7}{1.75}=\dfrac{3.7}{1.75}=2.114\\\\\\P(X

b) We have to calculatee P(x>47).

We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

z=\dfrac{X-\mu}{\sigma}=\dfrac{47-46.7}{1.75}=\dfrac{0.3}{1.75}=0.171\\\\\\P(X>47)=P(z>0.171)=0.4321

c) If the value differs 1.5 standard deviations from the mean value, we have a z-score of z=1.5

z=\dfrac{(\mu+1.5\sigma)-\mu}{\sigma}=\dfrac{1.5\sigma}{\sigma}=1.5

So the probability that maximum speed differs from the mean value by at most 1.5 standard deviations is P(-1.5<z<1.5):

P(-1.5

3 0
3 years ago
Coefficient x^2 in the expansion of (2+x)^5
Monica [59]
Alright, expand the given equation:
(2+x) (2+x) (2+x) (2+x) (2+x)
Use FOIL method and distribution to solve
At the final answer, find the x^2 and the number that multiplies to it is the coefficient
I can't do the actually expansion for you, it would take a decently long time. You should be able to, its a good practice. Good luck!
7 0
3 years ago
Find the derivative of 3e^y+x=y
Sindrei [870]

You have the following function:

y=3e^y+x

Derivate implictly the previous expression, as follow:

y^{\prime}=3e^yy^{\prime}+1

Where you have used that:

(e^y)^{\prime}=e^yy^{\prime}

Then, the implicit derivative of the given expression is:

y^{\prime}=3e^yy^{\prime}+1

Next, solve for y' as follow:

\begin{gathered} y^{\prime}-3e^yy^{\prime}=1 \\ (1-3e^y)y^{\prime}=1 \\ y^{\prime}=\frac{1}{1-3e^y} \end{gathered}

4 0
1 year ago
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