PLEASE HELP IM TIMED

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Furkat [3]

Answer:

D) 2, 4, 8, 16, 32

Step-by-step explanation:

We have given four sets of sequence.

And we have to find out which sequence is not an arithmetic sequence.

For this the given sequences should satisfy the value of common difference(d) and Arithmetic Progression formula.

A.P. Formula,

$T_n=a+(n-1)d$

Where $T_n$ = nth term of an A.P.

a = first term of an A.P.

n = number of terms.

d = common difference.

'd' is calculated by subtracting fist term from second term.

$d = second\ term-first\ term$

A) 4, 7, 10, 13, 16

$d = 7-4=3$

$d = 10-7=3$

Here d=3 and 5th term is 16.

So we find out the 5th term by using the formula of A.P. To check whether the sequence is in A.P. or not.

$T_5=4+(5-1)3=4+4\times\ 3=4+12=16$

Here the given sequence fulfills the condition of being in A.P.

Hence the given sequence is an arithmetic sequence.

B) 1, 2, 3, 4, 5

$d =2-1=1$

$d =3-2=1$

Here d=1 and 5th term is 5.

$T_5=1+(5-1)1=1+4=5$

Here the given sequence fulfills the condition of being in A.P.

Hence the given sequence is an arithmetic sequence.

C) 15, 9, 3, -3, -9

$d =9-15=-6$

$d =3-9=-6$

Here d=-6 and 5th term is -9.

$T_5=15+(5-1)-6=15+4\times -6=15+(-24)=-9$

Here the given sequence fulfills the condition of being in A.P.

Hence the given sequence is an arithmetic sequence.

D) 2, 4, 8, 16, 32

$d_1=4-2=2$

$d_2=8-4=4$

Here $d_1=2\ But\ d_2=4$

The common difference between the terms is not same.

In case of $d_1$ .

$T_5=2+(5-1)2=2+4\times 2=2+8=10$

In case of $d_2$ .

$T_5=2+(5-1)4=2+4\times 4=2+16=18$

Here the given sequence does not fulfills the condition of being in A.P.

Hence the given sequence is not an arithmetic sequence.

Hence the correct option is D) 2, 4, 8, 16, 32.

4 0

4 years ago

Which two angles in the figure are obtuse angles?

ValentinkaMS [17]

Answer: C. ∠SQP and ∠TQR

Step-by-step explanation:

Since, by the given diagram,

m∠TQR = m∠SQP (vertical angles)

And, m∠TQP < m∠TQR

By adding ∠TQR on both sides,

m∠TQP + m∠TQR < m∠TQR+m∠TQR

⇒m∠TQP + m∠TQR < 2 ∠TQR

⇒ 180° < 2 m∠TQR ( Because ∠TQP and ∠TQR are linear angles)

⇒ 90° < m∠TQR

Hence ∠TQR is a obtuse angle,

⇒ ∠SQP also is a obtuse angle.

4 0

3 years ago

water stations will be placed every 600 meters of a fifteen kilometer race. how many water stations will be needed?

Snezhnost [94]

1km=1000metres
15km=15000 metres
15000/600=25
25-1=24 (minus the last one)

hope this helps :)

5 0

3 years ago

Read 2 more answers

write the equation of the ellipse using the given information: the ellipse has foci (0,3) and (0,-3) and major vertices (0,5) an

svetlana [45]

Answer: (x^2)/16 + (y^2)/25 = 1

Step-by-step explanation:

According to the problem we can figure out that the center of the ellipse is (0,0).

Since the foci is (0,3) and (0,-3) we know that the value of c is 3. The major vertices are (0,5) and (0,-5) so the value of a is 5.

If we put this into the equation a^2=b^2 + c^2, we get 25=9+ b^2

We get b^2 is 16

Now since we know that the ellipse is vertical because the x value didn’t change, we know that the b^2 value comes first in the equation. Then the a^2 value which is 25.

5 0

3 years ago

Can someone help please?

ratelena [41]

Answer: It is TRUE. A point in a linear equation can be the solution to said equation.

4 0

3 years ago