Question

The perimeter of a rectangular field is 48m, if the length is twice the width . Find the area of the field.​

Answer 1

Answer:

128 m^2

Step-by-step explanation:

Perimeter = 48

(lenght  is twice the width)

total Lenght(both sides) = 4b

total height(both sides) = 2b

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4b +2b= 48

6b = 48

b = 48/6

b = 8

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lenght = 16

height = 8

bxh = 8*16 = 128

Answer 2

Answer:

Step-by-step explanation:

→Perimeter (P)  = 2×(L+W)              Perimeter = 48m

But Length = 2 × Width

∴ P = 2×( 2W + W)

       = 2×(3W)

  48 = 6W

Divide both sides by 6

          $\frac{48}{6}$ = $\frac{6}{6}$ W

∴Width (W) = 8m  

→This means Length = 2W

                                = 2×8m

                             L = 16m

→Area of a rectangle = L × W

                               = 8m × 16m

     ∴ Area of the rectangular field= $128m^{2}$