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Papessa [141]
4 years ago
6

NEED HELP DESPERATELY PLEASE IT IS MULTIPLE CHOICE​

Mathematics
1 answer:
Mashcka [7]4 years ago
7 0
The answer is (-1,-3) because the line passes through that point.
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Please help me with these I'm lost
Inessa [10]
Y = (2/3)x + 6
3y - 5x = 9

find an expression for y from the second equation:-
y = (5/3)x + 3
Now substitute this for y in the first equation:-
(5/3) x + 3 = (2/3)x + 6  Now solve for x:-
(5/3)x - (2/3)x  = 6 - 3
x = 3
Now plug x = 3 into the second equation to find the value of y:_
3y - 5(3) =9
3y = 15+9 = 24
y = 8
So the solution is x = 3, y = 8

written as a set this is {3,8}.
3 0
3 years ago
Chef Willie can make 54 pies in 2 hours. At this rate, how many pies can he make in 1 hour?
mihalych1998 [28]
27 pies in one hour 54=2 hours 54 divided by 2 equals 27
4 0
3 years ago
Which graph below is a tree graph? Place a pointer on your answer.​
Alex777 [14]

Answer:

b

Step-by-step explanation:

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6 0
3 years ago
erica is going to use the following ingredients to make pancakes for breakfast 2 1/2 cups of flour ,1/2 cups of sugar
nlexa [21]

I don't get it. Whats the question???

6 0
3 years ago
describe and correct the error a student made in finding the interval(s) over which the function is positive and negative
liraira [26]

Answer:

The interval over which the function is positive is (-1 , 3)

The interval over which the function is negative is (-∞ , -1)∪(3 , ∞)

Step-by-step explanation:

* Lets explain the meaning of The intervals of positive and negative

 values of a function

- Interval of positive values means the values of x when the values

 of y are positive

- Y is positive means the graph is above the x-axis

- Interval of negative values means the values of x when the values

 of y are negative

- Y is negative means the graph is below the x-axis

- <u><em>Remember</em></u> that the value of y on the x-axis is zero, then the points

 of intersection between the graph and x-axis have zero value of y

 and zero is not positive nor negative, then the x-coordinate of

 these points do not belong to the intervals of positive or negative

* <em>Lets solve the problem</em>

∵ The graph represents a downward parabola

∵ The positive value of the parabola is above the x-axis

∵ The parabola intersects the x-axis at -1 , 3

∴ Y is positive at ⇒ -1 < x < 3

# -1 , 3 ∉ to the interval

∴ The interval over which the function is positive is (-1 , 3)

∵ The negative value of the parabola is below the x-axis

∵ The parabola intersects the x-axis at -1 , 3

∴ Y is negative at ⇒ -∞ < x < -1 and 3 < x < ∞

# -1 , 3 ∉ to the interval

∴ The interval over which the function is negative is (-∞ , -1)∪(3 , ∞)

* <u><em>The error of the student he wrote Positive</em></u>: [-1 , 3] which means

  that -1 , 3 ∈ to the intervals over positive

  which the function is positive or negative

7 0
4 years ago
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