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Dominik [7]
2 years ago
12

A spool with 18 feet of ribbon will be cut into 8-inch segments. how many 8-inch segments can be cut from the spool of ribbon?

Mathematics
2 answers:
Kobotan [32]2 years ago
4 0

Answer:

27

Step-by-step explanation:

First, we convert 18 ft to inches.

18 × 12 in. = 216 in.

Now we divide 18 ft written as 216 in. by 8 in.

216 in. / 8 in. = 27

Answer: 27

Slav-nsk [51]2 years ago
4 0
27 is going to be your correct answer for this question.
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An arcade booth at a county fair has a person pick a coin from two possible coins available and then toss it. If the coin chosen
nydimaria [60]

Answer:

<em>b. 0.6024</em>

Step-by-step explanation:

<u>Conditional Probability</u>

Suppose two events A and B are not independent, i.e. they can occur simultaneously. It means there is a space where the intersection of A and B is not empty:

P(A\cap B) \neq 0

If we already know event B has occurred, we can compute the probability that event A has also occurred with the conditional probability formula

\displaystyle P(A|B)=\frac{P(A\cap B)}{P(B)}

Now analyze the situation presented in the question. Let's call F to the fair coin with 50%-50% probability to get heads-tails, and U to the unfair coin with 32%-68% to get heads-tails respectively.

Since the probability to pick either coin is one half each, we have

P(U)=P(F)=50\%=0.5

If we had picked the fair coin, the probability of getting heads is 0.5 also, so

P(F\cap H)=0.5\cdot 0.5=0.25

If we had picked the unfair coin, the probability of getting heads is 0.32, so

P(U\cap H)=0.32\cdot 0.5=0.16

Being A the event of choosing the fair coin, and B the event of getting heads, then

P(B)=P(F\cap H)+P(U\cap H)=0.25+0.16=0.41

P(A\cap B)=P(F\cap H)=0.25

\displaystyle P(A|B)=\frac{0.25}{0.41}=0.61

The closest answer is

b. 0.6024

7 0
3 years ago
27 millimeters multiplied by 1 cm/10 mm
Basile [38]
27 millimeters multiplied by 1 cm/10 mm= 2.7 centimeters

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Answer:

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