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Yuki888 [10]
2 years ago
6

Sumeet is building two types of birdhouses. The more traditional type takes 4 pieces of wood and 2 hours to build. The more lavi

sh type takes 10 pieces of wood and 7 hours to build. If he has a total of 46 pieces of wood and 29 hours to work, then how many of each type of birdhouse can he build?

Mathematics
1 answer:
mina [271]2 years ago
8 0

Answer:

The no. of traditional type birdhouses are 4 and the no. of lavish type birdhouses are 3.

Step-by-step explanation:

Let x be the no. of traditional type birdhouses

The more traditional type takes 4 pieces of wood and 2 hours to build.

One house requires wood = 4

x houses requires wood = 4x

One house requires time = 2 hours

x houses requires time = 2x

Let y be the no. of lavish type birdhouses

The more lavish type takes 10 pieces of wood and 7 hours to build.

One house requires wood = 10

y houses requires wood = 10y

One house requires time = 7 hours

y houses requires time = 7y

Now we are given that he has a total of 46 pieces of wood and 29 hours to work,

So, equations becomes : 4x+10y = 46\\2x+7y=29

Plot these equations on graph

4x+10y = 46 ---Blue line

2x+7y=29  ---Green line

Refer the attached figure

The intersection point provides the solution

Intersection point : (4,3)

So, x = 4 and y = 3

Hence the no. of traditional type birdhouses are 4 and the no. of lavish type birdhouses are 3.

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Answer:

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3 years ago
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jasenka [17]

Answer:

The number of child tickets sold was 75 and the number of adult tickets sold was 97

Step-by-step explanation:

<u><em>The correct question is</em></u>

At the movie theater child admission is $6.30 an adult admission is $9.60 on Wednesday 172 tickets were sold for a total sales of $1403.70 How many child tickets and adult tickets were sold that day?

Let

x ----> number of child tickets sold

y ----> number of adult tickets sold

we know that

x+y=172 ----> equation A

6.30x+9.60y=1,403.70 -----> equation B

Solve the system by graphing

Remember that the solution of the system is the intersection point both lines

Using a graphing tool

The intersection point is (75,97)

see the attached figure

therefore

The number of child tickets sold was 75 and the number of adult tickets sold was 97

8 0
3 years ago
A rectangular lamina of uniform density is situated with opposite corners at (0,0) and (15,4). calculate its radii of gyration a
Sphinxa [80]
First, you have to find the moment of inertia along the x and y axes. Constant density is denoted as k.


I_{x}= \int\limits^15_0\int\limits^4_0 {k y^{2} } \, dx  dy= \frac{1}{3}k (15-4)^4=4880.33k

I_{y}= \int\limits^15_0\int\limits^4_0 {k x^{2} } \, dx  dy= \frac{1}{3}k (15-4)^4=4880.33k

Then, the radii of gyration for

x = √[I_x/m]
y = [I_y/m]

where m = k(15-4)² = 121k. Then,

x = y = [4880.33k/121k] = 40.33

I hope I was able to help you. Have a good day.
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4x+6-5
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