The answer is C because my friend has told me it.
The answer is 63,800 mi²
hoped this helps
Answer:
To my calculations, I think its the first one, 4+2=2+4
I hope this helps! ^^
Apologizes if you get it wrong-
Step-by-step explanation:
v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
