Question

Find the equation of a line perpendicular to y=−6 that contains the point (1,3). Write the equation in slope-intercept form

Answer 1

Answer:

x=1

Step-by-step explanation:

Hi there!

We are given that a line is perpendicular to y = -6 and passes through the point (1, 3)

We want to write the equation of this line in slope-intercept form

Slope-intercept form is y=mx+b, where m is the slope and b is the value of y at the y intercept, hence the name

First, we need to find the slope (m) of the line

Remember that we were given that the line is perpendicular to y = -6

Perpendicular lines have slopes that multiply to get -1

The slope of y = -6 is 0; therefore, to find the slope of this line, we can do the following equation

0m=1

Divide both sides by 0

m = 1/0

This answer is undefined - therefore, the line has an undefined slope

If this is the case, then it means the line is a vertical line

A vertical line is written as x=k, where k is the value of x at the x intercept. It can't be written in slope-intercept form.

This value is also the value of x at every point that lies on such line - in this case, as given by the point (1, 3) , this value is 1

So substitute 1 as k.

x = 1

This is the line of the equation.

Hope this helps!