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aalyn [17]
3 years ago
7

This is due tomorrow help plz I'm begging it's #7

Mathematics
2 answers:
slava [35]3 years ago
5 0
The answer is A. If you look at the chart for option A, it show the equation
"x - 6/5". Basically saying that whatever the number is under the "x" on the left side of the chart all you do is subtract 1 and 1/5 (simplified form of 6/5).
kiruha [24]3 years ago
5 0
I believe the answer is A.
The question says that to get y you must use x-6/5. If you substitute each y value for x-6/5 then the only table that is correct is A.
Please don't hate if I'm wrong.
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Look at the coordinate plane.
Taya2010 [7]

Answer:

y = -3

Step-by-step explanation:

Desmos

7 0
2 years ago
In this cohort, 75% of the 32 students are right-handed. How many students are right-handed?
Sergio039 [100]
24 students are right-handed
5 0
2 years ago
A.Pet owners may have to take out a loan when their animal has a major operation. Buddy needs to have a surgery on his leg. The
jeyben [28]
$2,500 • 7.5% (or 0.075) = $187.50 (for one year).

For two years, the interested added onto the original price is $375 because $187.50 • 2 (years) = $375.

$2,500 + $375 = $2,875

The total of the cost of the surgery and the interest is $2,875.

Hope this helps! ❤️
3 0
3 years ago
a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was
Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em>\bar X<em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

          Z = \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean hours spent studying = 25 hours

            \sigma = standard deviation = 15 hours

            n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < \bar X < 30 hours)

    P(29 hours < \bar X < 30 hours) = P(\bar X < 30 hours) - P(\bar X \leq 29 hours)

      

    P(\bar X < 30 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } < \frac{ 30-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z < 2) = 0.97725

    P(\bar X \leq 29 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } \leq \frac{ 29-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z \leq 1.60) = 0.94520

                                                                    

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < \bar X < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0
2 years ago
PLZ HELP FAST <br><br> If you spend $3 on 6b apples, what is the unit rate (in dollars) per apple?
Ierofanga [76]

Answer:.

.50

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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