<u>(a) Construct a 95% confidence interval for the difference between the average number of intrusion attempts per day before and after the change of firewall setting (assume equal variance)</u>
Answer:
- 1/64 (x+4)² (x-3) (x-4) = 0
Step-by-step explanation:
f(x) = a (x+4)²(x-3)(x-4) ... curve touch (-4,0) and not cross x axis
x=0 f(x) = -3
a (4)² * (-3) * (-4) = -3
a = - 1/64
- 1/64 (x+4)² (x-3) (x-4) = 0
It is given in the question that
M is the MIDPOINT OF FG.
Since M is the midpoint of FG, therefore GM is half of FG. That is
Therefore
And FM is 13 too .
I haven't done this in a while, but I'm pretty sure the answer is D, (-3, -1.)
If you were to substitute x for -3 and y for -1 in the first inequalities and simplify, it would look like this:
-1 > -3-2
-1 > - 5
And that inequality is true, because -1 is bigger than -5. Let's also substitute in the other inequality, which would be:
-1 > 2(-3) + 2
-1 > -6 + 2
-1 > -4
And -1 is bigger than -4. So, I think the answer would be D because substituting for those values of x and y would stil. make the inequalities true.
Answer:
I believe that your answer should be B, because on the graph it shows that Mitchell is spending more money.
Correct me if i'm wrong.