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viva [34]
3 years ago
10

three roommates agreed to split the cost of food and rent evenly. last month they spent a total of 349.66 for food and 365 for r

ent. find the amount of the that each 3 roommates paid
Mathematics
1 answer:
barxatty [35]3 years ago
6 0
You devide $349.66 by is $116.55 and devide $365.00 by 3 is $121.06 so add $116.55 and $121.06 is about $237.61 each
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The first term of a sequence is 18, and the fifth term is 54. What is the common difference between each two consecutive terms?
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Answer:

9

Step-by-step explanation:

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(x+y+2)(y+1) <--- Please help,will mark brainly
kifflom [539]

Answer:

y^2+xy+x+3y+2

Step-by-step explanation:

first of all we have to multiplies the y in the second bracket for all numbers in the first bracket.

so we have:

xy+y^2+2y

now we have to do the same with 1

x+y+2

now we have to unite the two solutions

xy+y^2+2y+x+y+2

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6 0
3 years ago
Please help please please help please
zalisa [80]
Spinning on Y out of three letters (G, I and Y) = 1/3
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= 1/6
= 0.17

answer:
0.17

5 0
3 years ago
4. At Lilly's Bakery, the ideal weight of a loaf of bread is 24 ounces. By law, the actual weight can vary from
Fantom [35]
It can be 25.5 to 22.5
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3 years ago
Question: Researchers in Pakistan wanted to better understand the effects of anthracycline (a chemotherapeutic drug) on the hear
Sedbober [7]

Using the normal distribution, it is found that:

1. His z-score was of Z = -1.88.

2. There is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

3. Z-score of z = 1.85, there is a 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

4. Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of \mu = 1.35.
  • The standard deviation is of \sigma = 0.33.

Item 1:

Considering his ratio, we have that X = 0.73, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.73 - 1.35}{0.33}

Z = -1.88

His z-score was of Z = -1.88.

Item 2:

The probability is the <u>p-value of Z = -1.88</u>, hence, there is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

Item 3:

Score of X = 1.96, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.96 - 1.35}{0.33}

Z = 1.85

The probability is 1 subtracted by the p-value of Z = 1.85, hence, 1 - 0.9678 = 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

Item 4:

Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

More can be learned about the normal distribution at brainly.com/question/24663213

7 0
2 years ago
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