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koban [17]
2 years ago
6

If someone can answer all these ill give 100 points

Mathematics
1 answer:
Helga [31]2 years ago
4 0

Answer:

1. x = -6

2. x = 2

3. x = 6

4. x = 3

5. x = -5

6. x = -1

7. x = 0

8. x = 9

9. x = -4

10. x = 7

Step-by-step explanation:

1.

  • -10x = -8x + 12
  • -10x+8x=-8x+12+8x
  • -2x=12
  • -2x/-2=12/-2
  • x=-6

2.

  • 9-5x+x=1-x+x
  • -4x+9=1
  • -4x+9-9=1-9
  • -4x=-8
  • -4x/-4=-8/-4
  • x=2

3.

  • -2x+16-x=x-2-x
  • -3x+16=-2
  • -3x+16-16=-2-16
  • -3x=-18
  • -3x/3=-18/-3
  • x = 6

4.

  • (-4)(6x)+(-4)(-2)= -8x-40
  • -24x+8=-8x-40
  • -24x+8+8x=-8x-40
  • -16x+8=-40
  • -16x+8-8=-40-8
  • -16x=-48
  • -16x/-16=-48/-16
  • x=3

5.

  • 37 - 8x = (-7)(x)+(-7)(-6)
  • -8x+37=-7x+42
  • -8x + 37 + 7x = -7x + 42 + 7x
  • -x+37=42
  • -x+37-37=42-37
  • -x=5
  • -x/-1=5/-1
  • x=-5

6.

  • 6x+(-2)(2)+(-2)(8x) = 10 + 4x
  • 6x-4-16x = 10 + 4x
  • -10x - 4 = 4x + 10
  • -10x - 4 -4x=4x+10-4x
  • -14x-4=10
  • -14x-4+4=10+4
  • -14x=14
  • -14x/-14=14/-14
  • x=-1

7.

  • (-2)(x) + (-2)(1) = (2)(x) + (2)(-1)
  • -2x-2=2x-2
  • -2x-2-2x = 2x - 2 - 2x
  • -4x - 2 = -2
  • -4x-2+2=-2+2
  • -4x=0
  • -4x/-4=0/-4
  • x=0

8.

  • (-3)(x)+(-3)(3)=(-6)(x)+(-6)(-3)
  • -3x-9=-6x+18
  • -3x-9+6x=-6x+18+6x
  • 3x-9=18
  • 3x-9+9=18+9
  • 3x=27
  • 3x/3 = 27/3
  • x=9

9.

  • 6x-36=(-4)(-2x)+(-4)(7)
  • 6x-36= 8x -28
  • 6x-36-8x = 8x - 28 - 8x
  • -2x-36=-28
  • -2x-36+36=-28+36
  • -2x = 8
  • -2x/-2=8/-2
  • x=-4

10.

  • (2)(x)+(2)(1) = -2x + 30
  • 2x+2=-2x+30
  • 2x+2+2x=-2x+30+2x
  • 4x+2=30
  • 4x+2-2=30-2
  • 4x=28
  • 4x/4=28/4
  • x=7

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jenyasd209 [6]

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Step-by-step explanation: ONe way of solving a system of equations is using the Gauss-Jordan Elimination.

The method consists in transforming the system into an augmented matrix, which is writing the system in form of a matrix and then into a <u>Row</u> <u>Echelon</u> <u>Form,</u> which satisfies the following conditions:

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For this question, the matrix is a Row Echelon Form and is written as:

\left[\begin{array}{ccc}1&2&2\\0&1&3\\0&0&1\end{array}\right]\left[\begin{array}{ccc}4\\9\\-2\end{array}\right]

or in system form:

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