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Inessa05 [86]
3 years ago
6

Write the equation of the function g(x) if g(x) = f(x+2) +4 and f(x) = x^3 -7

Mathematics
1 answer:
omeli [17]3 years ago
4 0
F(x) = x³ - 7
f(x + 2) = (x + 2)³ - 7
f(x + 2) = (x + 2)(x + 2)(x + 2) - 7
f(x + 2) = (x(x + 2) + 2(x + 2))(x + 2) - 7
f(x + 2) = (x(x) + x(2) + 2(x) + 2(2))(x + 2) - 7
f(x + 2) = (x² + 2x + 2x + 4)(x + 2) - 7
f(x + 2) = (x² + 4x + 4)(x + 2) - 7
f(x + 2) = (x²(x + 2) + 4x(x + 2) + 4(x + 2)) - 7
f(x + 2) = (x²(x) + x²(2) + 4x(x) + 4x(2) + 4(x) + 4(2)) - 7
f(x + 2) = (x³ + 2x² + 4x² + 8x + 4x + 8) - 7
f(x + 2) = (x³ + 6x² + 12x + 8) - 7
f(x + 2) = x³ + 6x² + 12x + 8 - 7
f(x + 2) = x³ + 6x² + 12x + 1

g(x) = f(x + 2) + 4
g(x) = (x³ + 6x² + 12x + 1) + 4
g(x) = x³ + 6x² + 12x + 1 + 4
g(x) = x³ + 6x² + 12x + 5
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For what value of p will the pair of linear equations have infinitely many solutions (p-3)x + 3y = p , px+ py = 12
sleet_krkn [62]

Answer: p = 6


Step-by-step explanation:

HI !


 px + 3y - ( p-3)=0


a₁ = p , b₁ = 3 , c₁ = - (p-3)


=====================


12x + py - p=0


a₂ = 12  , b₂ = p , c₂ = -p


since , the equations have infinite solutions , 


a₁/a₂ = b₁/b₂ = c₁/c₂


p/12 = 3/p =  p-3/p



--------------------------------------


p/12 = 3/p


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p² = 36


p = √36

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for the value of p = 6 , the equations will have infinitely many solutions





5 0
3 years ago
Of the 30 cars in a parking lot, 12 are blue, 8 are red, 6 are white, and 4 are silver. In simplest form, what are the odds in f
Radda [10]

Answer:

Step-by-step explanation:

8+6=14

14/30 = 7/15

So the final answer is 7/15

pls thank me pls :(

3 0
2 years ago
Add. <br> (−2+6x^3−3x^2)+(4x^3−5+x^2)
Gemiola [76]

Answer:

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Step-by-step explanation:

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so 6x^3 + 4x^3 and that would be 10x^3

then -3x^2 + x^2 and the negative is larger so it would be -2x^2

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7 0
2 years ago
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