Answer:
7) C) PQR ≈ TSR
8) B) 3
9) D) 102 ft
10) D) 21
11) C) 45
Step-by-step explanation:
7) C) PQR ≈ TSR
8) 2 * 6 = 12
so 4x = 12
x = 3
9)
24/20 = x/85
x = 24 * 85 / 20
x = 202 ft
10)
QT/35 = 24/40
QT/35 = 3/5
QT = 35 * 3 / 5
QT = 21
11)
ΔKLM ≈ΔXYZ
9/4 = 2.25
So
XY = 9 ---> given
YZ = 7 * 2.25 = 15.75
XZ = 9 * 2.25 = 20.25
Perimeter ΔXYZ = 9 + 15.75 + 20.25 = 45
Answer:
well, we only no that
2l + 2w is 80
(lengths and widths on all 4 sides
and that w * l is A
so the function should be w times what's left for l, but also expressed by something with w
2l + 2w = 80 | -2w
2l = 80 -2w | devide by 2
l = 80 - w
now we can substitute l in
A = w * l
so that we only need w's
A(w) = w * (80-w)
for any w it will give us the area, makes only sense for 0<w<80
Answer:
Step-by-step explanation:
Let q represent the number of quarters (the higher-value coin). Then 8-q is the number of dimes, and Jill's total amount in change is ...
0.25q +0.10(8-q) = 1.25
0.15q + 0.80 = 1.25 . . . . . . . eliminate parentheses
0.15q = 0.45 . . . . . . . . . . . . . subtract 0.80
q = 3 . . . . . . . . . . . . . . . . . . . . divide by 0.15
the number of dimes is 8-q = 8-3 = 5.
Jill has 3 quarters and 5 dimes.
<span>5 - {-(-2)}
</span>5 - {+2} (negative + negative = positive)
<span>5 - 2 (negative + positive = negative)
</span>3