Please help! Quadratic equations!
1 answer:
Answer:
Step-by-step explanation:
Assume that the quadratic term of this equation has no coefficient. One can set the equation up in factored form using the given roots. Then expand the equation and simplify the equation to convert to standard form.
The equation in factored form is the following,
Expand, multiply every term in one of the parenthesis by every term in the other,
Simplify,
You might be interested in
9514 1404 393
Answer:
The given graph shows a function of x.
Step-by-step explanation:
Neither 1 nor 3 is a single-valued relation for some values of x. The graph shown passes the vertical line test, so does represent a function.
The graph is a relation that is a function of x.
___
The attached graph is of the equation of 3. A vertical line will intersect the graph in more than one place, so the relation is NOT a function.
9514 1404 393
Answer:
- maximum: 2
- minimum: -6
Step-by-step explanation:
The extrema will be at the ends of the interval or at a critical point within the interval.
The derivative of the function is ...
f'(x) = 3x² -4x -4 = (x -2)(3x +2)
It is zero at x=-2/3 and at x=2. Only the latter critical point is in the interval. Since the leading coefficient of this cubic is positive, the right-most critical point is a local minimum. The coordinates of interest in this interval are ...
f(0) = 2
f(2) = ((2 -2)(2) -4)(2) +2 = -8 +2 = -6
f(3) = ((3 -2)(3) -4)(3) +2 = -3 +2 = -1
The absolute maximum on the interval is f(0) = 2.
The absolute minimum on the interval is f(2) = -6.
