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katen-ka-za [31]
2 years ago
15

Solve each equation 3x^2=80

Mathematics
1 answer:
Lapatulllka [165]2 years ago
5 0

Answer:

x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}

or

x = \frac{\pm4\sqrt{15}}{3}

Step-by-step explanation:

Hello!

Use the quadratic formula: x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

First, let's convert our equation to standard form of a Quadratic: ax² + bx + c = 0

3x² = 80

3x² - 80 = 0

Note, thats the value of b will be 0, as there is no "bx"

Now, solve:

  • x = \frac{-(0) \pm \sqrt{(0)^2 - 4(3)(-80)}}{2(3)}        Plug in values
  • x = \frac{\pm\sqrt{960}}{6}                              Simplify the radical (Discriminant)
  • x = \frac{\pm8\sqrt{15}}{6}                              Pull out perfect squares
  • x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}              Reduce factors

 

The solutions are x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}

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