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podryga [215]
2 years ago
15

Find the area to the nearest hundredth use 3.14 for π​

Mathematics
1 answer:
aliina [53]2 years ago
5 0

Answer:

50.24

Step-by-step explanation:

you can use pi r^2

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A rectangle has a height of k^2+3k 2 +3k, squared, plus, 3 and a width of k^2+7k 2 +7k, squared, plus, 7. Express the area of th
vlada-n [284]

Answer: k^4+10k^3+21k^2

Step-by-step explanation:

Given

Height of rectangle is h=k^2+3k

Width is w=k^2+7k

The area of the rectangle is given by the multiplication of the height and width

\Rightarrow A=\left(k^2+3k\right)\left(k^2+7k\right)\\\\\Rightarrow A=k^2k^2+k^2\cdot \:7k+3kk^2+3k\cdot \:7k\\\\\Rightarrow A=k^4+10k^3+21k^2

Thus, the area of the rectangle is k^4+10k^3+21k^2.

3 0
3 years ago
please please please please please please please please please please help me with the answer for this question...(HOW MANY TERM
tia_tia [17]

Answer:The answer can be calculated by doing the following steps;

Step-by-step explanation:

I think you have done some mistakes in question because at one stage there comes a complex no. And at the end the value of n comes in decimal.

4 0
3 years ago
ASAP JUST ANSWER THX
DochEvi [55]

Answer:

The second one

Step-by-step explanation:

Y=11/4x+3/2

4 0
3 years ago
Would It be unusual if a random sample of 400 adults results in 156 or more having no credit cards
vesna_86 [32]

Answer:

Yes, in places like the US, UK and other bigger areas

No, in like Africa and poorer areas

5 0
3 years ago
Indicate the equation of the line, in standard form, that passes through (2, -4) and has a slope of 3/5. Enter your answer into
Papessa [141]

keeping in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-4})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{3}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{\cfrac{3}{5}}(x-\stackrel{x_1}{2})\implies y+4=\cfrac{3}{5}x-\cfrac{6}{5}

\bf \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{5}}{5(y+4)=5\left( \cfrac{3}{5}x-\cfrac{6}{5} \right)}\implies 5y+20=3x-6\implies 5y=3x-26 \\\\\\ -3x+5y=-26\implies 3x-5y=26

6 0
4 years ago
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