Answer:
![y=-\dfrac{1}{2}x+2](https://tex.z-dn.net/?f=y%3D-%5Cdfrac%7B1%7D%7B2%7Dx%2B2)
Step-by-step explanation:
Define two points on the line:
![\textsf{let}\:(x_1,y_1)=(0,2)](https://tex.z-dn.net/?f=%5Ctextsf%7Blet%7D%5C%3A%28x_1%2Cy_1%29%3D%280%2C2%29)
![\textsf{let}\:(x_2,y_2)=(4,0)](https://tex.z-dn.net/?f=%5Ctextsf%7Blet%7D%5C%3A%28x_2%2Cy_2%29%3D%284%2C0%29)
Use the slope formula and the defined points to find the slope:
![\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0-2}{4-0}=-\dfrac{1}{2}](https://tex.z-dn.net/?f=%5Cimplies%20%5Ctextsf%7Bslope%7D%5C%3A%28m%29%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%3D%5Cdfrac%7B0-2%7D%7B4-0%7D%3D-%5Cdfrac%7B1%7D%7B2%7D)
Substitute the found slope and one of the points into the point-slope form of a linear equation:
![\implies y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=%5Cimplies%20y-y_1%3Dm%28x-x_1%29)
![\implies y-2=-\dfrac{1}{2}(x-0)](https://tex.z-dn.net/?f=%5Cimplies%20y-2%3D-%5Cdfrac%7B1%7D%7B2%7D%28x-0%29)
Simplify:
![\implies y-2=-\dfrac{1}{2}x](https://tex.z-dn.net/?f=%5Cimplies%20y-2%3D-%5Cdfrac%7B1%7D%7B2%7Dx)
![\implies y=-\dfrac{1}{2}x+2](https://tex.z-dn.net/?f=%5Cimplies%20y%3D-%5Cdfrac%7B1%7D%7B2%7Dx%2B2)
Answer:
x = 10
Step-by-step explanation:
Here, we are tasked with calculating the value of x.
To do this, we need the picture of the wordings given in the question.
please check the attachment for a pictorial representation.
Now the theorem to use is that , the exterior angle of a triangle is equals the sum of the two opposite interior angle.
Thus, mathematically;
3x + 11 + 3x + 15 = 10x -14
6x + 26 = 10x -14
10x-6x = 26 + 14
4x = 40
x = 40/4
x = 10
D. (3 x 13) x 42
is your answer
just change the parenthesis from (13 x 42) to (3 x 13), since you will still get the same answer (using associative property of multiplication)
hope this helps :D